Of course to make it even stranger
sparql -v "select * where {BIND(substr(str("1234567890"), 0, 11) AS
?substr)}"
Does work as expected!
Regards,
Jerven
1 SELECT ?substr
2 WHERE
3 { BIND(substr(str(1234567890), 0, 11) AS ?substr) }
16:13:39 INFO exec :: QUERY
SELECT ?substr
WHERE
{ BIND(substr(str(1234567890), 0, 11) AS ?substr) }
16:13:39 INFO exec :: ALGEBRA
(project (?substr)
(extend ((?substr "1234567890"))
(table unit)))
On 11/06/2017 03:45 PM, Jerven Tjalling Bolleman wrote:
Dear Andy,
That makes it very strange because this is what I get
$ sparql --version
Jena: VERSION: 3.4.0
Jena: BUILD_DATE: 2017-07-17T11:43:07+0000
ARQ: VERSION: 3.4.0
ARQ: BUILD_DATE: 2017-07-17T11:43:07+0000
RIOT: VERSION: 3.4.0
RIOT: BUILD_DATE: 2017-07-17T11:43:07+0000
$ sparql -v "select ?substr where {BIND(substr("1234567890", 0, 11) AS
?substr)}"
1 SELECT ?substr
2 WHERE
3 { BIND(substr(1234567890, 0, 11) AS ?substr) }
15:43:31 INFO exec :: QUERY
SELECT ?substr
WHERE
{ BIND(substr(1234567890, 0, 11) AS ?substr) }
15:43:31 INFO exec :: ALGEBRA
(project (?substr)
(extend ((?substr (substr 1234567890 0 11)))
(table unit)))
----------
| substr |
==========
| |
----------
Regards,
Jerven
On 11/06/2017 03:34 PM, Andy Seaborne wrote:
I get "1234567890" (jena v 3.5.0)
sparql -v 'select ?substr where {BIND(substr("1234567890", 0, 11) AS
?substr)}'
1 SELECT ?substr
2 WHERE
3 { BIND(substr("1234567890", 0, 11) AS ?substr) }
----------------
| substr |
================
| "1234567890" |
----------------
I get this for versions back to 2.10.0.
Andy
On 06/11/17 14:22, Jerven Tjalling Bolleman wrote:
Dear Jena-Devs,
I believe that the following query
select ?substr where {BIND(substr("1234567890", 0, 11) AS ?substr)}
should return
| substr |
================
| "1234567890" |
instead of the current
| substr |
==========
| |
I take this from reading the spec here.
https://www.w3.org/TR/xpath-functions/#func-substring
If people agree with my reading I will be happy to submit a patch.
Regards,
Jerven
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