I try with this parameters for the kannel .
$str="username=".USER."&password=".PASSWORD."&from={$this->vc_to}&to={$this->vc_from}&udh=&text=".urlencode($item['vc_mensaje'])."&smsc=transmitter&dlr-mask=31&dlr-url=".urlencode("http://url.com/dlr.php?ss=ss&smt=%t&i=%i&n=%n&A=%A&B=%B&F=%F&p=%p&P=%P&m=%m&c=%c&M=%M&C=%C&d=%d&L=%L&b=%b&U=%U&u=%u&r=%r&otra=mas&smsc-id=%i&status=%d&answer=%A&to=%P&from=%p&ts=%t");
Use this parameters for capture all , only have the first response ,
status = 8 , but no have the next answer in the url,
the URL http://url.com/dlr.php only save the request.
On 27/04/10 23:45, Benaiad wrote:
Hi Sergio,
I think you can get the entire dlr message text by adding
'&something=%A' to your dlr url.
Regards.
--
Benaiad
On Tue, Apr 27, 2010 at 3:56 PM, Sergio Gallegos
<[email protected] <mailto:[email protected]>> wrote:
Hi,
i hope can u help me with this problem , i need recover the
answer of the operator , but i can't, the answer is of type
message , the log is this:
2010-04-23 13:17:20 [14852] [3] INFO: smsbox: Got HTTP request
</cgi-bin/sendsms> from <192.168.1.1>
2010-04-23 13:17:20 [14852] [3] INFO: sendsms used by <outis>
2010-04-23 13:17:20 [14852] [3] INFO: sendsms sender:(outis:XXXX>
(192.168.1.1) to:(111111> msg:( Respuesta desde la XXXX>
2010-04-23 13:17:20 [14852] [4] INFO: Starting delivery report
<outis> from <XXXX>
2010-04-23 13:17:26 [14852] [4] INFO: Starting to service <ID:
8c52c STAT: false AUTH: 13> from <XXXX> to <111111>
Needed sending to URL the value of AUTH , but i dont know how to.