Thanks for your help.
Well I wanted to get the position of each scalar, as the loop does; I'll
be content to use a loop
Thanks for your time.
Paul
Le 2016-12-28 14:43, Samuel Gougeon a écrit :
> Le 28/12/2016 09:16, [email protected] a écrit :
>
>> Hi all
>>
>> I do not understand why the following code does not work when I try
>> to
>> use vectorization (many trials)?
>>
>> What am I doing wrong ?
>>
>> Thanks
>>
>> Paul
>> ################################################################
>>
>> mode(0)
>>
>> A = [ 1 2 9 0 10 6 ; 5 3 8 8 0 9 ; 5 9 1 0 3 9]'
>> v = [2 9 6]'
>>
>> index = zeros(3,1);
>> for i = 1 : 3
>> index(i) = find(A(:,1) == v(i));
>> end
>> disp(index)
>>
>> i = [1 : 3]';
>> index2 = zeros(3,1); //pause
>> index2(i,1) = find(A(:,1) == v(i,1));
>
> Actually, what you want and try to do is unclear. Even members() could
> be not appropriate.
> You can easily get an error even with your unvectorized version, as
> soon as one of the v components will appears several times in A(:,1)
>
> SG
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