Hi,
Check out this solution:
[vs,k] = gsort(v,'g','i');
[aux,ka,kb] = intersect(vs,A(:,1));
index = kb(k)
index =
2. 3. 6.
Regards,
Rafael
From: users [mailto:[email protected]] On Behalf Of
[email protected]
Sent: Wednesday, December 28, 2016 2:59 PM
To: Users mailing list for Scilab <[email protected]>
Subject: Re: [Scilab-users] find & vectorization
Thanks for your help.
Well I wanted to get the position of each scalar, as the loop does; I'll be
content to use a loop
Thanks for your time.
Paul
Le 2016-12-28 14:43, Samuel Gougeon a écrit :
Le 28/12/2016 09:16, [email protected]<mailto:[email protected]> a écrit :
Hi all
I do not understand why the following code does not work when I try
to
use vectorization (many trials)?
What am I doing wrong ?
Thanks
Paul
################################################################
mode(0)
A = [ 1 2 9 0 10 6 ; 5 3 8 8 0 9 ; 5 9 1 0 3 9]'
v = [2 9 6]'
index = zeros(3,1);
for i = 1 : 3
index(i) = find(A(:,1) == v(i));
end
disp(index)
i = [1 : 3]';
index2 = zeros(3,1); //pause
index2(i,1) = find(A(:,1) == v(i,1));
Actually, what you want and try to do is unclear. Even members() could
be not appropriate.
You can easily get an error even with your unvectorized version, as
soon as one of the v components will appears several times in A(:,1)
SG
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