Try the following, without loops, inspired by a solution by B. Mohandes : --> x = [1.1 1.1 3.2; 2.3 1.1 1.1; 4.7 5.2 5.2] x = 1.1 1.1 3.2 2.3 1.1 1.1 4.7 5.2 5.2
--> y = unique(x); y0 = [min(y)-1; y]; y(find(histc(y0,x(:),%F)==1)) ans = 2.3 3.2 4.7 Regards, Rafael -----Original Message----- From: users <[email protected]> On Behalf Of Stéphane Mottelet Sent: Friday, July 5, 2019 7:24 PM To: [email protected] Subject: Re: [Scilab-users] Finding elements occuring once in a matrix Hello, Maybe not optimal, but does the job: x = [1 1 3 2 1 1 4 5 5]; f = []; for y=unique(x(:))' if length(find(x==y)) == 1 f = [f y]; end end --> f f = 2. 3. 4. S. Le 05/07/2019 à 18:03, Izabela Wójcik-Grząba a écrit : > Hello, > > Is there a simple way of finding elements of matrix which occurs only > once. For example in this matrix it would be 3 and 4: > [1 1 3 > 2 1 1 > 4 5 5] > > For the time being I couldn't find any smart idea for that. Could you > help? > > Kind regards, > Iza -- Stéphane Mottelet Ingénieur de recherche EA 4297 Transformations Intégrées de la Matière Renouvelable Département Génie des Procédés Industriels Sorbonne Universités - Université de Technologie de Compiègne CS 60319, 60203 Compiègne cedex Tel : +33(0)344234688 http://www.utc.fr/~mottelet _______________________________________________ users mailing list [email protected] http://lists.scilab.org/mailman/listinfo/users
