Raphael, Stephane,
Thanks a lot for your quick reaction and help.
Best regards,
Iza
W dniu 05.07.2019 20:23, Rafael Guerra napisał(a):
Try the following, without loops, inspired by a solution by B. Mohandes
:
--> x = [1.1 1.1 3.2; 2.3 1.1 1.1; 4.7 5.2 5.2]
x =
1.1 1.1 3.2
2.3 1.1 1.1
4.7 5.2 5.2
--> y = unique(x); y0 = [min(y)-1; y]; y(find(histc(y0,x(:),%F)==1))
ans =
2.3
3.2
4.7
Regards,
Rafael
-----Original Message-----
From: users <[email protected]> On Behalf Of Stéphane
Mottelet
Sent: Friday, July 5, 2019 7:24 PM
To: [email protected]
Subject: Re: [Scilab-users] Finding elements occuring once in a matrix
Hello,
Maybe not optimal, but does the job:
x = [1 1 3
2 1 1
4 5 5];
f = [];
for y=unique(x(:))'
if length(find(x==y)) == 1
f = [f y];
end
end
--> f
f =
2. 3. 4.
S.
Le 05/07/2019 à 18:03, Izabela Wójcik-Grząba a écrit :
Hello,
Is there a simple way of finding elements of matrix which occurs only
once. For example in this matrix it would be 3 and 4:
[1 1 3
2 1 1
4 5 5]
For the time being I couldn't find any smart idea for that. Could you
help?
Kind regards,
Iza
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