I did as u said 
public class AuditSignOutPage extends SignOutPage
{
        
        public AuditSignOutPage() {
                ((AuditWebSession)(Session.get())).signout();
                setRedirect(true);
                throw new RestartResponseException(SSISignOutPage.class);
        }
}


public class SSISignOutPage extends UnSecuredBasePage {

        public SSISignOutPage() {
                add(new AjaxLink<Void>("relogin"){
                        @Override
                        public void onClick(AjaxRequestTarget target) {
                                setResponsePage(new
AuditWicketApplication.SignInPageHelper().getSignInPage());
                                setRedirect(true);
                        }
                });
        }
}
I click on the signout link   AuditSignOutPage   invalidates  the session
and send to   SSISignOutPage   .here this page gets loaded , I see the link
relogin.

when  I click on the link relogin it should take me to my signinpage but
again i am ending up with session expired page .  I  set the break point  
in onClick method   but it never goes there , 

please explain me what could be causing this ? 



Mauro Ciancio wrote:
> 
>   In order to implement my sign out page I've created a SignOutPage
> that invokes the signOut method in AuthenticatedWebSession, then
> setRedirect(true) and as final step I throw a:
> 
> throw new RestartResponseException(HomePage.class).
> 
>   This makes the home page be processed (and the url in the navigation
> bar remains /your_home_page_url).
> 
> Here is the full code if you need it:
> 
> public class LogOutPage extends WebPage {
> 
>     public LogOutPage() {
>         AuthenticatedWebSession.get().signOut();
>         setRedirect(true);
>         throw new RestartResponseException(HomePage.class);
>     }
> }
> 
> Cheers.
> 
> On Thu, Mar 25, 2010 at 11:19 AM, fachhoch <[email protected]> wrote:
>>
>> I initially tried   etResponsePage(SSISignOutPage.class)  it did not
>> worked ,
>> so used the new approach ,
>>
>> regarding what my  SSISignOutPage it does nothing except for showing a
>> link
>> ,  before to that the control never goes to the page constructor ,
>>
>> I am assuming after a session is invalidated wicket removes all  its
>> pages
>> from page map and  its possible that it cannot find the page
>> SSISignOutPage
>> and for that reason do I get pageExpired error ?
>>
>>
>>
>>
>> christian.giambalvo wrote:
>>>
>>> Depends on what your SSISignOutPage.class does.
>>> But why don't use setResponsePage(SSISignOutPage.class) ??
>>>
>>> -----Ursprüngliche Nachricht-----
>>> Von: tubin gen [mailto:[email protected]]
>>> Gesendet: Donnerstag, 25. März 2010 12:59
>>> An: users
>>> Betreff: signout and redirect
>>>
>>> here is my code to signout link.
>>>
>>> add(new Link<Void>("signout"){
>>> @Override
>>> public void onClick() {
>>> ((AuditWebSession)(Session.get())).signout();
>>> throw new RestartResponseException(SSISignOutPage.class);
>>> }
>>> });
>>>
>>> when user clicks on signout I expect to go to SSISignOutPage.
>>> but I end up with a  different page which is set in applicationsettings
>>>
>>> IApplicationSettings settings= super.getApplicationSettings();
>>> settings.setPageExpiredErrorPage(SessionExpiredPage.class);
>>>
>>>
>>> the  SessionExpiredPage .
>>> please tell me what could be causing this ?
>>>
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>>>
>>>
>>
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>>
>>
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>>
> 
> 
> 
> -- 
> Mauro Ciancio <maurociancio at gmail dot com>
> 
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> 
> 
> 

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