This works for me:
final Link signOutLink = new Link("signOutLink")
{
public void onClick()
{
getSession().invalidate();
setResponsePage(getApplication().getHomePage());
setRedirect(true);
}
public boolean isVisible()
{
return ((MySessionClass)getSession()).isSignedIn();
}
};
I put that in my "base page" class so that it's visible everywhere.
On Thu, Mar 25, 2010 at 11:30 AM, fachhoch <[email protected]> wrote:
>
> I did as u said
> public class AuditSignOutPage extends SignOutPage
> {
>
> public AuditSignOutPage() {
> ((AuditWebSession)(Session.get())).signout();
> setRedirect(true);
> throw new RestartResponseException(SSISignOutPage.class);
> }
> }
>
>
> public class SSISignOutPage extends UnSecuredBasePage {
>
> public SSISignOutPage() {
> add(new AjaxLink<Void>("relogin"){
> �...@override
> public void onClick(AjaxRequestTarget target) {
> setResponsePage(new
> AuditWicketApplication.SignInPageHelper().getSignInPage());
> setRedirect(true);
> }
> });
> }
> }
> I click on the signout link AuditSignOutPage invalidates the session
> and send to SSISignOutPage .here this page gets loaded , I see the link
> relogin.
>
> when I click on the link relogin it should take me to my signinpage but
> again i am ending up with session expired page . I set the break point
> in onClick method but it never goes there ,
>
> please explain me what could be causing this ?
>
>
>
> Mauro Ciancio wrote:
>>
>> In order to implement my sign out page I've created a SignOutPage
>> that invokes the signOut method in AuthenticatedWebSession, then
>> setRedirect(true) and as final step I throw a:
>>
>> throw new RestartResponseException(HomePage.class).
>>
>> This makes the home page be processed (and the url in the navigation
>> bar remains /your_home_page_url).
>>
>> Here is the full code if you need it:
>>
>> public class LogOutPage extends WebPage {
>>
>> public LogOutPage() {
>> AuthenticatedWebSession.get().signOut();
>> setRedirect(true);
>> throw new RestartResponseException(HomePage.class);
>> }
>> }
>>
>> Cheers.
>>
>> On Thu, Mar 25, 2010 at 11:19 AM, fachhoch <[email protected]> wrote:
>>>
>>> I initially tried etResponsePage(SSISignOutPage.class) it did not
>>> worked ,
>>> so used the new approach ,
>>>
>>> regarding what my SSISignOutPage it does nothing except for showing a
>>> link
>>> , before to that the control never goes to the page constructor ,
>>>
>>> I am assuming after a session is invalidated wicket removes all its
>>> pages
>>> from page map and its possible that it cannot find the page
>>> SSISignOutPage
>>> and for that reason do I get pageExpired error ?
>>>
>>>
>>>
>>>
>>> christian.giambalvo wrote:
>>>>
>>>> Depends on what your SSISignOutPage.class does.
>>>> But why don't use setResponsePage(SSISignOutPage.class) ??
>>>>
>>>> -----Ursprüngliche Nachricht-----
>>>> Von: tubin gen [mailto:[email protected]]
>>>> Gesendet: Donnerstag, 25. März 2010 12:59
>>>> An: users
>>>> Betreff: signout and redirect
>>>>
>>>> here is my code to signout link.
>>>>
>>>> add(new Link<Void>("signout"){
>>>> @Override
>>>> public void onClick() {
>>>> ((AuditWebSession)(Session.get())).signout();
>>>> throw new RestartResponseException(SSISignOutPage.class);
>>>> }
>>>> });
>>>>
>>>> when user clicks on signout I expect to go to SSISignOutPage.
>>>> but I end up with a different page which is set in applicationsettings
>>>>
>>>> IApplicationSettings settings= super.getApplicationSettings();
>>>> settings.setPageExpiredErrorPage(SessionExpiredPage.class);
>>>>
>>>>
>>>> the SessionExpiredPage .
>>>> please tell me what could be causing this ?
>>>>
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>>>>
>>>>
>>>>
>>>
>>> --
>>> View this message in context:
>>> http://old.nabble.com/signout-and-redirect-tp28027857p28029507.html
>>> Sent from the Wicket - User mailing list archive at Nabble.com.
>>>
>>>
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>>>
>>>
>>
>>
>>
>> --
>> Mauro Ciancio <maurociancio at gmail dot com>
>>
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>>
>>
>>
>
> --
> View this message in context:
> http://old.nabble.com/signout-and-redirect-tp28027857p28030542.html
> Sent from the Wicket - User mailing list archive at Nabble.com.
>
>
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