Hi Alex,
I tried your code and stripped it down as much as possible and couldn't
find anything wrong with it. My guess is that Wicket ajax does not
remove timers from replaced components in ajax responses. Therefore, the
javascript timeout function is still executed on the client even if its
related component is removed from the page.
Please file a JIRA issue. I suggest using the simpler version below as a
quickstart:
HomePage.html
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd";>
<html xmlns:wicket="http://wicket.apache.org";>
<body>
<a href="#" wicket:id="remove">Replace the panel with attached time
behavior</a><br>
<span wicket:id="fragments">WMC</span>
</body>
</html>
HomePage.java
import org.apache.log4j.Logger;
import org.apache.wicket.Component;
import org.apache.wicket.util.time.Duration;
import org.apache.wicket.ajax.AbstractAjaxTimerBehavior;
import org.apache.wicket.ajax.AjaxRequestTarget;
import org.apache.wicket.ajax.markup.html.AjaxLink;
import org.apache.wicket.markup.html.WebMarkupContainer;
import org.apache.wicket.markup.html.WebPage;
public class HomePage extends WebPage {
private static final Logger LOGGER = Logger.getLogger(HomePage.class);
private static final String TIMER_COMPONENT_ID = "fragments";
public HomePage() {
Component fragment = new WebMarkupContainer(TIMER_COMPONENT_ID);
fragment.add(new AbstractAjaxTimerBehavior(Duration.seconds(2)) {
@Override
protected void onTimer(AjaxRequestTarget target) {
LOGGER.error("Timeout");
}
});
add(fragment.setOutputMarkupId(true));
add(new AjaxLink("remove") {
@Override
public void onClick(AjaxRequestTarget target) {
Component fragment = new
WebMarkupContainer(TIMER_COMPONENT_ID);
HomePage.this.replace(fragment);
target.add(fragment);
}
});
}
}
Bertrand
On 01/08/2012 3:34 AM, Alex66955 wrote:
TestParent.java
TestParent.html
TestChild.java
TestChild.html
Output:
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