I guess you do not understand the formula . Lets see if I can help. If you take the numbers that you just used in your email they will prove it to you . Ex 1 : 78.6 ft lb torque x 6000 rpm / 5250 = 89.83 hp Your second Ex : 106.6hp at approx 8000rpm . You say over 80000 rpm 106.6 x 5250 / 8500 = 65.84 Ft lb torque . Pistons , flywheels , cyl. heads , bore , stroke , etc..... Have nothing to do with the formula . Here is something to think about . All engines will hit their peak torque at approxamately 75 % of the rpm that max Hp is achieved . Eric H. [EMAIL PROTECTED] wrote: > > Hp = (Torque x rpm)/5250 > > The formula above would be correct if your Vmax had an electric motor > measured at radius of 12 inches. > > This is not correct for a combustion engine. There are many factors which > will determine the torque output of an engine. Such as a flywheel, the > engines bore and stroke, piston weight, drive train, wheel diameter, etc. > > Look at the Dyno run for a Bone Stock bike from the web site. At > approximately 6000 rpm, a maximum torque of 78.6 ft-lbs are recorded with 90 > hp. This is far below the maximum horsepower reading at over 8000 rpm where > it reads 106.6 hp and the torque at that point is below 70 ft-lbs. > > If the formula was correct, all engines would make the maximum torque when > the maximum Hp is achieved but they don't. > > John > ............................................. > To unsubscribe go to http://www.sayegh.org/unsubscribe.htm > ............................................. ............................................. To unsubscribe go to http://www.sayegh.org/unsubscribe.htm .............................................
