Jed, looking at figure 6, the Oct 21 data I calculate that the average power is 1.3888 watts. That is 20 watts * 500 seconds / 7200 seconds = 1.3888 watts. If Mizuno applies that amount of power continuously what would you expect the temperature to do? It is obvious that no internally generated power will be seen which would contribute to the total measured by the calorimeter.
I could perform that calculation with my limited knowledge of the system, but it would be better for someone like yourself to give an accurate answer. My gut feeling is that the temperature would increase along a constant slope once the transients are settled down. This slope should be much lower than the average seen under normal operating conditions. Also, can you verify that the water flow rate is actually nominally 8 liters per minute? Much of my discussion about kinetic heating is based upon this number. I assume it was measured at some point in time. Thanks, Dave -----Original Message----- From: Jed Rothwell <jedrothw...@gmail.com> To: vortex-l <vortex-l@eskimo.com> Sent: Sat, Jan 10, 2015 1:28 pm Subject: Re: [Vo]:"Report on Mizuno's Adiabatic Calorimetry" revised Bob Cook <frobertc...@hotmail.com> wrote: Jed should identify the actual time the reaction stopped "hours before that event" failure of the pump. You can see it in the graph. The reaction peters out around hour 6 where the blue line starts to fall, and the pump fails at hour 8. The end of the reaction at hour 6 looks the same as it does on other days. This is Fig. 15 here: http://lenr-canr.org/acrobat/RothwellJreportonmi.pdf - Jed
