There is an opinion around that says that all atoms that comprise rydberg matter are entangled.
In this state, a cluster of N atoms form a lattice in which each member of this aggregation is identical to all the other members of the aggregation. That means that all the atoms act in lock step so that the aggregation can be considered a superatom. For this to be so, all individual atoms are in the same energy state, all electrons are synchronized in their orbits, all spins are identical, it can be thought of as all members of the aggregation are identical twins. On Thu, May 12, 2016 at 2:34 PM, Bob Cook <[email protected]> wrote: > One key feature that Higgins has identified is the nature of the outer > (way out) electron. He noted that it is planar in nature and the outer > electron can exhibit different shapes and angular momentum and interact > with nuclei. in the RM to hold it together---a bond. Such bonding > suggests a coherent QM system. > > I would conjecture that if Li were the nuclei that had formed RM that such > a loose electron might also interact with other local nuclei, for example > H and or Ni in a solid state nano system to form a fairly large coherent > system. The low energy changes may resonate with energy changes of nuclei > and provide a mechanism for transfer of nuclear energy to the loose > electrons of the coherent system. Different RM orbitals may, as Higgins > suggests, provide a variety of spin and angular momentum equivalent to > phonic (vibrational) energy for the nano system. A large enough system may > be able to accept a large amount of nuclear energy that is associated with > transmutation or fusion of nuclei. System temperatures with its > characteristic spectrum of phonic energy, magnetic fields (either static or > variable) and other forms of small energy additions and/or removal, may all > be important in establishing energy and angular momentum states within a > coherent system to allow a major nuclear transition to occur. > > It should be noted that the ambient magnetic field acts to establish > energy states for the loosely bound electrons and may orient the RM to > facilitate coupling of nuclear magnetic states with the electron orbital > states. > > One thought about the dense RM is that the use of lasers may be to > actually cool the atoms to remove energy of their electrons. Laser cooling > is used to reach very low cryogenic temperatures. The common notion that > the Holmlid laser adds energy may be wrong. I am not sure what the > experimental data suggests is happening. Holmlid statements would seem to > indicate that energy is removed to form his suspected dense H(0) which then > reacts to provide the excess energy, muons etc. > > Bob Cook > > *From:* Bob Higgins <[email protected]> > *Sent:* Wednesday, May 11, 2016 1:10 PM > *To:* [email protected] > *Subject:* Re: [Vo]:Rydberg Matter and electron orbitals > > In RM of hydrogen, I there is only one electron, and it is in the orbital > for that high energy state. Maybe it is considered a Rydberg orbital, > where the S orbital would be lower (ground) energy and spherical. I don't > know much about RM with other atoms, but I think it is just an outer > electron in such a Rydberg orbital and the rest of the electrons are pretty > much in their ordinary orbitals as though it were an ion, having lost one > electron. The Rydberg electron would be so far away, as far as the rest of > the electrons were concerned, it probably seems like it is gone. > > On Wed, May 11, 2016 at 1:02 PM, Stephen Cooke <[email protected] > > wrote: > >> Thanks Bob, >> >> That it helps a lot I must admit I have a lot to learn about Rydberg >> matter. Would these highly excited and Bohr atom like elliptical orbitals >> still correspond to some kind of quantum mechanical orbital? Perhaps a >> highly excited S orbital or something? Even highly excited P, D, F and G >> orbitals would tend to have more complex shapes I think? I suppose it would >> depend on the orbitals angular momentum. I suppose we might also need to >> consider the spin as well as angular momentum though in the models if >> quantum mechanical models are used. Perhaps at these energies the Bohr >> Model fits better the observed behavior. >> >> >> On 11 mei 2016, at 20:05, Bob Higgins <[email protected]> wrote: >> >> Stephen, My understanding is that Rydberg hydrogen is highly excited >> hydrogen - it is just below an energy that the hydrogen would be ionized. >> In fact, small energy inputs to hydrogen in a Rydberg state will ionize >> it. As I understand the orbitals for Rydberg state hydrogen they are huge >> diameter flattened ellipsoids. Because of this, it is not too far off to >> consider it like a Bohr model. In Rydberg Matter (RM), all of the atoms >> have an electron in a large flattened ellipsoid shape which now loops some >> of the other nuclei in the RM to hold it together. RM naturally forms as a >> large planar "snowflake", but can easily be warped in a field gradient. RM >> is well characterized from its rotational spectrum. >> >> OTOH, the ultra-dense form is nearly pure imagination at this point, >> based on very slim data. If an ultra-dense form happens, how could it be >> formed from high energy matter like RM? Normally the very small is only >> achieved when substantial energy is removed from the system. >> >> On Wed, May 11, 2016 at 10:26 AM, Stephen Cooke < >> [email protected]> wrote: >> >>> Has anyone looked at RM from the point of view of quantum mechanical >>> electron orbitals? If so could you help me understand some crazy thoughts >>> and questions I have about it ? >>> >>> I understand Rydberg hydrogen matter typically forms from excited >>> hydrogen atoms in some way. >>> >>> Most literature seems to represent the electron orbits in Rydberg >>> Hydrogen in a classical Bohr electron shell representation. >>> >>> What is the case in the quantum mechanical model? Are the electrons >>> excited to particular states such as S2 or P2 orbitals? I suppose the >>> electrons are more easily excited to P2 from the S1 orbital if excited by >>> photon absorption for example. >>> >>> Does the type of RM depend on the type of orbitals the electrons are in? >>> For example using Holmlid definitions is a S2 more likely to form H(1) type >>> RM and P2 more likely to form H(0). Naively looking at the dumbbell shape >>> of P2 orbitals does this allow closer approach of the nuclei than say S2 >>> with its spherical orbital? >>> >>> I think it's not so straight forward though as I think in Holmlid's >>> recent paper he mentions the orbital angular momentum (l) in each state. >>> Particular electron orbital types have particular orbitals. S orbitals have >>> l=0, P orbitals have l=1 etc. however he mentions that H(0) and D(0) have >>> l=0 and H(1) and D(1) have l>0. This is the opposite than I suggested above >>> suggesting that in fact the S orbitals allow the more compact configuration >>> of RM and P and other Orbital types can form normal RM. >>> >>> On another matter are the orbitals themselves affected in the dense form >>> of H(0) bearing in mind the very close spacing if the nuclei a few pm >>> compared to the normal S1 orbital radius? Also does the vortex nature of >>> the close combinations of atomic pairs into threads impact the electron >>> orbitals? >>> >>> >>> >> >> >
