CD Sites— I have for some time been of the mind that nuclear potential energy tied up in a lattice of coherent (entangled) particles is transfered to the lattice electrons in the form of spin orbital momentum—phonic energy during LENR.
In the Pd system with D at high loading a small BEC of D nuclei could form and then fuse to He g iven the correct conditions involving EM coupling to link neutron and proton magnetic moments with magnetic moments of the Pd lattice electrons. In this regard I consider it takes a relatively strong local B field to accomplish the necessary coupling with the neutron and proton making up a D nucleus. The BEC status of D’s within the lattice would allow their close approach during a reaction forming a He nucleus. The potential energy released would not result in energetic particles or EM radiation, but only phonic (spin) energy spread across the entire lattice. With proper resonant coupling and many BEC within a single lattice a larger, more energetic, reaction occurs releasing enough phonic energy to destroy the lattice or to create a bosenova. The reactions suggested above seem to fit observations from Pd system LENR testing IMHO. Bob Cook. From: CB Sites<mailto:[email protected]> Sent: Tuesday, June 13, 2017 3:49 PM To: vortex-l<mailto:[email protected]> Subject: Re: [Vo]:Bose Einstein Condensate formed at Room Temperature I'm kind of late on this, but would spin conservation do what Ed Storm asked? "However, why would only a few hydrons fuse leaving just enough unreacted hydrons available to carry all the energy without it producing energetic radiation? I would expect occasionally,many hydrons would fuse leaving too few unreacted hydrons so that the dissipated energy would have to be very energetic and easily detected." If I remember, Steve and Talbot Chubbs had proposed that bose band states could distribute the energy over many nucleons in the band state. In a 1D kronig-penny model of a periodic potential, H and D form bands and their band energy levels are separated by a 0.2eV, which means when 20MeV is spread across the band, the spectrum would be 20MeV / (n * 0.2eV) where n are the number of hyrons making up the band. That's just back of the envelope using a 2D kronig-penny period potential. And all of that photon energy spread over n-hydrons gets dumped right back into the lattice. Similar in a sense to the Mossbauer effect. On Tue, Jun 13, 2017 at 6:50 PM, Axil Axil <[email protected]<mailto:[email protected]>> wrote: http://physicsworld.com/cws/article/news/2017/jun/12/superfluid-polaritons-seen-at-room-temperature Superfluid polaritons seen at room temperature the polaritons behave like a fluid that can flow without friction around obstacles, which were formed by using a laser to burn small holes in the organic material. This is interpreted by the researchers as being a signature of the superfluid behaviour. there might be some sort of link between a superfluid and a Bose–Einstein condensate (BEC) – the latter being a state of matter in which all constituent particles have condensed into a single quantum state. He was proved right in 1995 when superfluidity was observed in BECs made from ultracold atoms On Thu, Jun 8, 2017 at 1:54 PM, Axil Axil <[email protected]<mailto:[email protected]>> wrote: A Bose condinsate brings super radiance and super absorption into play. These mechanisms produce concentration, storage, and amplification of low level energy and goes as "N", the number of items in the condinsate. On Thu, Jun 8, 2017 at 9:46 AM, Frank Znidarsic <[email protected]<mailto:[email protected]>> wrote: Why is a Bose Condensate needed? Its a matter of size and energy. The smaller the size of something we want to see the more energy it takes. Using low energy radar you will never be able to read something as small as this text. You need to go to UV energies to study atoms. Higher ionizing energies are needed to study the nuclear forces. Really high energy accelerator energies are required to look at subatomic particles. The common complaint physicists have with cold fusion is that the energy levels are to low to induce any type of nuclear reaction. They never, however, considered the energy levels of a large hundreds of atoms wide condensed nano-particle. Its energy levels are quite low. Warm thermal vibrations appear to the nano particle as a high energy excitation. This again is a matter of its size. It's not cracks, or shrunken atoms at work. It is the thermal excitation of a nano particle that yields the required energy. Again the simulation induces a velocity of one million meters per second. Frank Z
