It would be nice to read the entire paper in order to find out the source of the gamma radiation. Is the reaction due to one isolated gamma or a continuous intense beam of gammas as might be applied from a tuned gamma laser?
The tuned gamma laser may be the dark technology being applied in a controlled manner to induce decay of constituent components of the relatively weakly coupled U -235 nucleus. The isomeric states of U-235 are well known and likely subject to stimulation by a tuned EM source. The EM induced transition may cause the simultaneous decay of a constituent muon or alpha trapped in the U-235 nucleus. What is needed is a high energy electron scattering experiment follow up to look at the nuclear ash, which should be available in sufficient quantit to produce the excess heat being noted. Such electron scattering testing has revealed detailed nuclear structure that indicates the presence of muons within neutrons and protons. Bob Cook Sent from Mail<https://go.microsoft.com/fwlink/?LinkId=550986> for Windows 10 ________________________________ From: JonesBeene <jone...@pacbell.net> Sent: Friday, April 20, 2018 3:55:18 PM To: firstname.lastname@example.org Subject: RE: [Vo]:Cold Fusion Catalyzed Hot Fission - A promising hybrid or just hand-waving? Robin, * The 8.8 MeV gamma may have enough energy to fission the U all by itself through giant dipole resonance. Yes, that could happen but the probability is low. Spontaneous fission is also possible but unlikely. They are saying that deuterium disintegration is relatively high probability. * When a neutron is added to U235 to create U236, only about 6.5 MeV is released, which is less than 8.8 MeV, yet addition of the neutron is sufficient to fission the nucleus. Not sure that I understand what you are saying. The mass of the neutron is around a GeV which is going to trigger a chain of events following a prompt release - and when fusion happens due to the massive destabilization following the absorption, the net energy release within a short time is around 50 MeV plus several free neutrons which can continue the chain reaction. However, the potential importance of this paper, if it can be believed, is that a mystery particle(s) result from deuterium disintegration– ala Holmlid except with gamma irradiation instead of laser irradiation. But in this case, apparently the mystery particle continues a chain reaction, with or without neutrons. He should be clearer of course. It would be hugely important - if it were true.