K shells are not usually vacant, so such an electron would still upset
things. Regards,
You miss the point! If you increase the nuclear charge by +2 then
exactly 2 k-shell electrons are missing!
(If you understand the energy levels ...)
Jürg Wyttenbach
Am 24.07.19 um 04:46 schrieb [email protected]:
In reply to Jürg Wyttenbach's message of Sun, 21 Jul 2019 18:39:48 +0200:
Hi,
[snip]
Bob
One reason why the D* path is working like adding +2p/2e could be that
the internal electron from the neutron only needs to do a little push to
get to the k-shell. Thus no need to emit an electron!
K shells are not usually vacant, so such an electron would still upset things.
Regards,
Robin van Spaandonk
local asymmetry = temporary success
--
Jürg Wyttenbach
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