Robin—
If the electron is slow enough, I would guess it very well may react with other atomic electrons and be absorbed producing a charge on the system and a small increase in phonic energy. For all practical purposes it would not be observed except for a small charge , accumulated with repeated like LENR reactions. Bob Cook Sent from Mail<https://go.microsoft.com/fwlink/?LinkId=550986> for Windows 10 ________________________________ From: [email protected] <[email protected]> Sent: Tuesday, July 23, 2019 6:46:04 PM To: [email protected] <[email protected]> Subject: Re: [Vo]:If Mizuno is correct, this design is likely tobetheprecursor to all future devices In reply to Jürg Wyttenbach's message of Sun, 21 Jul 2019 18:39:48 +0200: Hi, [snip] >Bob > >One reason why the D* path is working like adding +2p/2e could be that >the internal electron from the neutron only needs to do a little push to >get to the k-shell. Thus no need to emit an electron! K shells are not usually vacant, so such an electron would still upset things. Regards, Robin van Spaandonk local asymmetry = temporary success
