Hi, If the Bohr radius electron is a toroid with the Bohr radius as the major radius, and the classical electron radius as the minor radius, then with both rotational velocities equal at alpha x c we get two rotational frequencies, one with the minor radius, and one with the major radius.
For the major radius we get: (alpha x c)/(2 x Pi x r_sub_Bohr) and for the minor radius we get (alpha x c)/(2 x Pi x classical_electron_radius) Multiplying each of these frequencies by Planck's constant yields equivalent photon energies. The first works out to 27.2 eV (Mills' "energy hole"), and the second works out to 511 keV, which is the mass/energy of the electron. Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition provides the motivation, Cooperation provides the means.
