In reply to Frederick Sparber's message of Sat, 4 Mar 2006 20:00:16 -0700: Hi, [snip] >Robin. > >The closest shape for spin and the moment of inertia ( I ) to meet > mvr = h/2(pi) = I * 2(pi)f is a flat-wavy disk particle I = 1/2 MR^2 >or standing on edge MR^2 > >An abbreviated list of moments of inertia: > >http://en.wikipedia.org/wiki/List_of_moments_of_inertia > >Or You can figure out ( I ) for a torus from this. :-) > >http://scienceworld.wolfram.com/physics/MomentofInertiaTorus.html
This is for a solid torus, and I'm not sure whether the mass is inside, on, or outside the torus. Nevertheless, taking it at face value, one would only get a difference in angular momentum of 2 parts in a billion, assuming a torus with the dimensions given, and I think that's probably near the limit of current measurements anyway. However I also wonder how anyone knows that the angular momentum actually is h/2xPi? I.e. how is it measured, and which geometrical assumptions are applied to the measurement? (i.e. that value appears to come from assuming the electron is a point particle spinning around at the Bohr radius). [snip] Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition provides the motivation, Cooperation provides the means.
