Michel wrote:
>
> I am still curious about how one can measure gravitational pull (or push) > on electrons with a fieldless tube :)
>
Electrically fieldless, but not gravity fieldless, Michel.
If electrons are released at the bottom and gravity repels them upward,
I think a Faraday Cup can be used to detect them.
In the meantime.
The gravitational force on a 1 kg mass at the earth's surface
is G * Me * 1/R^2 = 6.67e-11 * 5.98e24 * 1/R^2 = 9.8 newtons
OTOH, The red-shift is GM/[R*c^2]
But M/c^= Energy = 9e16 joule/kg
Thus in terms of energy E, G' = 8.23e-45
Thus for the force F on a 1.0 kg mass at the earth's surface:
F = 8.23e-45 * 5.98e24 * 9e16 * 1.0 * 9e16/6.38e6^2 = 9.8 newtons
But, according to red-shift G is based on 1/R
So F = 8.23e-45 * 5.98e24 * 9e16 * 1.0 * 9e16/6.38e6 = 6.25e7 newtons
Thus 1/R Energy G = G' = 8.23e-45 * 6.38e6 = 5.253e-38
Hence the force F between the energy mc^2 of two 1.0 kg masses
at 1.0 meter separation:
F = 5.25e-38 * 9.0e16^2 = 4.255e-4 newtons
And between the earth and 1.0 joule of (Localized Energy):
F = 5.25e-38 * 5.98e24 * 9.0e16/6.38e6 = 4.43e-3 newtons
Which is close to the values of Repulsion Electrogravity Force
that Buehler obtained in his experiments.
Also the 5.25e-38 number is close to the calculated
4.77e-38 coulomb "Hypocharge"..
Bona fide Numerology?
Fred
