If no such charge or current is detected, then gravity attracts
electrons.
No Fred I disagree with your conclusion, there could be no electron arriving
at 0.3s simply because they all had sufficient velocity to arrive earlier.
Or there could be some, but gravity force is classically downwards and they
were about to fall back
If you don't know the initial velocities you can't conclude, hence my
suggestion to use the "volunteers" whose initial velocity we know very
precisely (1/2*m*v0^2=h*nu-W) and can make as small as desired with a
retarding electrode (1/2*m*v0^2=h*nu-W-e*V), and whose flight time will
depend on the direction of gravity.
Michel
----- Original Message -----
From: "Frederick Sparber" <[EMAIL PROTECTED]>
To: "vortex-l" <[email protected]>
Sent: Friday, April 14, 2006 9:59 PM
Subject: Re: Electrogravity & Proton Repulsion of Electrons
Starting from scratch, Michel.
Attractive forces acting on the electron at or near the earth's surface.
1, At the Bohr Radius 8.24e-8 newton
2, Attached to an H2O molecule 6.4e-11 newtons
3, The earth's fair weather field 2.0e-17 newtons
4, The earth's gravity field attractive 8.9e-30 newtons,
5, or could it be gravity repelled 8.9e-30 newtons?
In the latter case, if it is released in an evacuated vertical
tube the direction of force, 4, or 5, can be determined, provided
the tube is virtually free of extraneous electrical fields.
Shining a pulse of light on a Cs-CsO film on a silver-plated
foil placed on the bottom of the tube and looking for
arrival of the electrons about 0.3 seconds or so later
(3.0 meters/sec or so) using a faraday cup tied to an electrometer
capable of femto-coulomb or femto-ampere currents
(and the LED or other Photon source) at the top.
If no such charge or current is detected, then gravity attracts
electrons.
Fred
