delta G, Gibbs Free Energy from CRC tables.
H-OH - 56.687
OH + 8.18
HO-OH - 28.78
H +48.58
H2 0.00
O + 55.39
O2 0.00
H + OH + E = H-OH
E = - 56.69 + 8.18 +48.58 = 0.073
2 H-OH + O2 + E = 4 OH
E = 2 (56.687) + 4 ( 8.18)
E = 113.374 + 32.72
E = 146.094
4 OH + E = 2 HO-OH
E = 2 (-28.78) + 4 (8.18)
E = - 24.84
2 HO-OH + E = 2 H-OH + O2
E = 2 (-56.687) + 2 (28.78)
E = - 113.374 + 28.78 + 28.78
E = - 55.814
OTOH, on Nickel and/or Stainless Steel surfaces that have been
exposed to atmospheric O2 the O2 dissociates into bound
O atoms ( 2 * 55.39 = 110.78 kcal/mole free energy)
and adsorbed water dissociates to bound H + OH.
See around pages 305 and up:
Then 2 H-OH + 2 O = 4 OH
2 H-OH + 2 O + E = 4 OH
E = 113.37 - 110.78 +32.72
E = 35.31
And if this correct blame it on Chocolate. :-)
Fred
