The name is Jullian with an "a". If by "incomptent" you mean "doesn't compute well" yes that's what I "seemed to imply" ;-)
BTW the fact that power is not equal to Iav*Vav in the general case (I'll let you find an obvious example where P is not zero whereas Iav or Vav is null, which would make the Iav*Vav method infinitely underestimate input power i.e. overestimate the COP), and so can't be relied on when dealing with spiky currents and voltages, applies to all electrical power measurements, whether input or output. Michel ----- Original Message ----- From: "Harry Veeder" <[EMAIL PROTECTED]> To: <[email protected]> Sent: Tuesday, June 06, 2006 7:00 AM Subject: Re: Battery shapes > > So is Naudin incomptent when it comes to calculating power output? (That is > what Michel Jullien seem to imply.) > > Harry >
