----- Original Message -----
From: "Michel Jullian" <[EMAIL PROTECTED]>
Subject: Re: Battery shapes
<snip>> the instrument will calculate
the instantnaeous power for each sample and integrate ***not average***
them
to a true power measurement.
They integrate over a time interval to get total energy (joules) in that
interval, and then they divide by the time interval to get... (fill in the
blank Mike ;)
I thnk you are right. RMS is used for measurements of I or E independantly,
but where instantaneous I and E are available as in the TI instrument,
integration of the intantaneous I*E product will gibve a correct average,
but averaging I and E separately will not.
Mike Carrell
