I wrote:
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Yes, the total super-positioned E field nets to about zero, but the way that happens is by a change in charge distribution. That change in charge distribution has effects. The electron fugacity in the cathode builds. Looking at Fig. 3 in

http://www.mtaonline.net/~hheffner/Szpak.pdf

The E field is neutralized by the distribution of charges in the electrolyte changing, and by an increase in the electron charge density in the cathode. In the plastic the charge distribution changes by displacement of the nuclei from the atomic centers of charge. The increase in negative ion charges in the electrolyte near the plastic is offset by an increase in positive ion charges near the cathode (ion charge balances to zero in the electrolyte).

We have a voltage divider. Initially most of the voltage drop is through the plastic. Beyond the plastic most of the voltage drop is through the 2 molecule thick interface. However, as electrolysis proceeds and loading reaches its peak, the conductivity of the top layer of the electrolyte diminishes. Much of the voltage drop starts to occur right in the cathode surface. At this time the fugacity of the electrons builds right there - in the cathode surface, but not very deep, provided the material is tough enough to sustain the voltage drop without diffusion losses. This place of high electron fugacity, high deuteron fugacity, low deuteron mobility, low conductivity, is the active zone for fusion. It takes a while to build in some electrode materials and is never achieved at all in many. - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

It seemed to make sense to me at the time I wrote it, but now I have serious doubts. It seems to me that a constant current power supply (used in many CF experiments) would drive up the voltage and thus electron fugacity as the electrode gained electrode resistance and the external E field would not have so much effect.

Perhaps using a power supply floating on a high resistance would provide a higher negative potential for the electrode and cell as a whole, and a higher electron fugacity in the cathode.


       Electrolysis
        potential
            (+)--PowerSupply---(-)
I I---------------resistor---------- Ground
        -----I------------------I-----
        |    I                  I    |
  (++)  |    I                  I    |    Key:
    c   |    #                  I    |
c | # I | I - Electrolysis power wire
    c   |    #                  I    |       # - Platinum screen anode
    c   |    #                  I    |       g - Gold foil
    c   |    #                  I    |       s - Piezo substrate
    c   |                       I    |       p - Deposited Pd
c | ggg I | -| - Clear plastic cell wall c | pgsgIIIIIIIIIIIIIIII | c - Copper foil HV electrode
    c   |    pgs                     |
    c   |    pgs                     |
    c   |    pgs                     |
    c   |    pgs                     |
    c   |    pgsg                    |
    c   |     ggg                    |
    c   |                            |
    c   |    #                       |
    c   |    #                       |
    c   |    #                       |
    c   |    #                       |
    c   |    #                       |
    c   |                            |
    c   ------------------------------
    c
    c
    c
    c  Foil 1

       Fig. 4 - Diagram of Floating Power Szpak's cell


Horace Heffner
http://www.mtaonline.net/~hheffner/



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