I just noticed the process is energetically allowed to continue
another step. Consider:
Mass of particles
(in AMU)
57.935346 Ni58
1.007825 p
-58.939503 Cu59
==========
0.003668
The energy excess is therefore (0.003668 AMU)* (931.5 MeV/(AMU/c^2) =
3.4167 MeV/c^3. Cu59 decays by positron emission ( with 1.36 m half-
life) into Ni59, which decays ( with 7.6x10^4 y half life) by E.C. to
Co59, if I have all that right. This provides a possible explanation
for excess heat in Ni+H experiments, though maybe not because Ni59
should be readily detectable, as would positron annihilation gammas.
The presence of a deflated electron in the post fusion nucleus along
with the prospective positron might lead to radiation in small
increments directly from the nucleus, instead of production of an
annihilation gamma from an emitted positron. Perhaps Co59 is produced
directly, avoiding the intermediate steps.
In any case, a clear lesson from this discussion is that Fe alloy
electrodes (perhaps Fe-Ni-B) should be tested in high temperature gas
loading (of ordinary hydrogen) conditions, as well as in ordinary HV
electrolysis, possibly using a boric acid or sodium metasilicate
electrolyte in HV AC electrolysis to passify the surface.
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
