On Dec 15, 2008, at 5:30 PM, [email protected] wrote:
In reply to Horace Heffner's message of Mon, 15 Dec 2008 16:49:51
-0900:
Hi,
[snip]
Under conventional theories, making Ni58 from Fe56 requires
substantial energy to supply the extra mass. This is on the downward
sloping side of the curve of binding energy. Consider:
Mass of particles
(in AMU)
55.934939 Fe56
1.007825 p
1.007825 p
-57.935346 Ni58
==========
0.015243
This is an *excess* mass (the final product has less mass than the
ingredients).
IOW the reaction produces energy, which BTW is 14.2 MeV, not 1.4.
Right on both counts! I shouldn't post calculations when I'm in too
big a hurry to proof read. The results are still in my calculator. I
missed the exponent on the energy.
The energy deficit is therefore (0.015243 AMU)* (931.5 MeV/(AMU/c^2)
= 1.4198 MeV/c^3.
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
