You forgot to include mechanical E... In Harry Veeder's recent post, Sean (Steorn) is quoted as saying, "...to be clear, as the rotor speeds up the mechanical power increases, the electrical power remains the same and the power to heat remains the same."
So, does that mean that below some RPM its <U, and above that RPM it >U? According to the schedule, which they have been holding to, we should be able to answer that question by the end of Jan. -Mark -----Original Message----- From: Stephen A. Lawrence [mailto:[email protected]] Sent: Saturday, January 16, 2010 7:07 PM To: [email protected] Subject: Re: [Vo]:More from Inductance thread in Steorn forum On 01/16/2010 08:38 PM, Harry Veeder wrote: > Steorn: Ok there is a whole load of things mixed up here. If we take a > classical view of any system, there are no losses or gains, just > changes in forms of energy. So your comment that the diode increases > losses is just not true - it changes theform of some of the energy > conversion. > > As for the change in inductance - its independent of rotational speed. > > The amount of energy converted to heat thru Joule heating reduces per > revolution, but the amount of heat power produced is always the same > (same dutycycle, no BEMF). SAY WHAT???? Is that not exactly what Bill Beaty has been saying? As the motor revs up the resistive heat (i.e., the losses in the coils, the "Joule heating") drops. But that is the chain of reasoning that leads to the conclusion that it's not OU, so it can't be what was meant here. No virus found in this incoming message. Checked by AVG - www.avg.com Version: 9.0.725 / Virus Database: 270.14.142/2623 - Release Date: 01/15/10 23:35:00
