At 03:50 PM 5/12/2010, Jones Beene wrote:
-----Original Message-----
From: Abd ul-Rahman Lomax
> Shanahan's cigarette-lighter explanation does not
factor for the lack of excess heat when doing this with hydrogen.
Well, at the risk of defending a "repulsive" argument, many experiments do
show excess heat with hydrogen, including some of the Arata experiments. [...]
No. Arata does not show excess heat with hydrogen. He shows the
normal heat of formation of palladium hydride (same as with
deuterium). He uses hydrogen as a control, showing the extra heat
with deuterium. There are other experiments of other kinds that may
show excess heat with hydrogen. My sense is that there are many kinds
of possible reactions, under different conditions. Not just one.
However, some low level of effect may be possible with hydrogen due
to the presence of deuterium in it. That's a different story.
However, with H2 the heat generated is most likely NOT nuclear. With D2 some
of the heat may not be nuclear, either. Excess heat with H2 or D2 could be
related to Mills "shrinkage" or to ZPE. With D2, it is even possible that
actual fusion may be a time reversed QM "balancing act" and only replaces
energy lost in other methods.
The formation of palladium deuteride is exothermic. Thus, like most
evaporations, the escape of deuterium from the lattice must cool it.
Slowly. In the cigarette lighter, this effect is swamped by
recombination with oxygen from the air.
