Frank, I find your idea interesting. I've worked through your basic equations and have included them simply because I spent so much time on them, I figured I should do something with them. :)
In the palladium lattice, when the molecules are stimulated such that they are vibrating near the transitional frequency, I understand from your theory that the coulombic barrier opens up. Do you have a way to calculate the size of the coulombic barrier at this point? Thanks, Craig --------------------------- The theory postulates that for energy to travel from space into matter, an impedance match must occur. Frank calculates the speed of transition to be equal to 1,094,000 meters / second, which is, essentially, the speed of sound within the nucleus of an atom. Once he calculates this number, he notices a lot of little interesting things. For instance: this speed can be translated into a vibrational frequency in the nucleus, and all electron orbitals are at integer multiples of a wavelength calculated from the frequency and the speed. To calculate the speed of transition, (Vt) 1) Newton's Law F=ma Now, what we're going to do is use classical equations to solve for the speed of sound in the nucleus, from the vibrational frequency in the nucleus. 2) Coulomb's Law Calculate the maximum force between 2 protons. This is also the force between the proton and electron in a hydrogen atom at the ground state. Maximum force occurs at the Coulombic Barrier and can be calculated from Coulomb's law. Fmax = Q^2 / (4 * pi * e0) * (2Rc)^2) Q = charge of a proton = 1.602176487*10^−19 Coulombs e0 = permittivity of free space = 8.854187817*10^−12 (http://en.wikipedia.org/wiki/Vacuum_permittivity) Rc = the radius of the Coulombic barrier. This is also known as the classical radius of a proton. Fmax = Q^2 / ( 4 * pi * e0 (2*1.409 x 10-15 )^2 ) = 29.053 Newtons Fmax = 29.053 Newtons 3) The equation for simple harmonic motion as applied to a simple vibrating nucleus. f = (1/(2 * pi)) * sqrt (k/m) f = frequency m = mass = average mass of nucleons k = spring constant = Fmax / Rn, where Rn = displacement, from Hooke's Law. Rn = 1.36 * 10^-15 = radius of a proton 4) Frequency (f) can be turned into a speed by multiplying both sides of the equation by the distance covered during a vibration. This is 2 * displacement. Vt = (1/(2*pi)) * sqrt (k/m) * 2Rn k = Fmax / Rn Vt = (1/(2*pi)) * sqrt ((Fmax / Rn) / m) * 2Rn m = mass of proton = 1.67*10^-27 kg Rn = radius of a proton = 1.36*10^-15 meters Vt = (1/(2*pi)) * sqrt((29.053 / (2*1.36e-15)) / 1.67e-27) * (2*1.36e-15) = 1,094,817.78 Vt = 1,094,817 m/s This is the speed of transition, and the number Frank wants to call Znidarsic's Constant. It represents the speed of sound in a nucleus. Since we're talking about a vibrational speed, we can go back to a frequency and a wavelength. 5) Vt = f*w f = frequency w = wavelength w = Vt / f This is the wavelength of a photon inside of the nucleus, not the emitted photon. 6) This is the equation for capacitance. C = e0 * A / D C = Capacitance e0 = Permittivity of Free Space A = Area between D = Distance Let's assume that the wavelength of a photon in the nucleus carries a capacitance. Twice the wavelength would be the area, and 1/2 the wavelength would be used instead of the distance between the plates of a capacitor, in the equation. C = e0 * w^2 / 0.5 * w C = 2*e0*w Substituting for wavelength: C = 2*e0*Vt / f This is the capacitance of energy in the transitional state. 7) E = Q^2 / 2 * C Q = Charge C = Capacitance E = Energy Substituting E = (Q^2 / 4 * e0 * Vt) * f E = h * f (This is Einstein's Photo-Electric Equation) h = Planck's Constant > > > >
