In reply to Man on Bridges's message of Sat, 22 Jan 2011 05:06:04 +0100: Hi, [snip] >Based upon natural presence and absence of radiation I would probably go >for this on: >62Ni28 + p* --> 63Cu29 + 6.122 MeV [-1.984 MeV] (B_Ni:28) > >62Ni28 : pres. 3.634 % >1H1 : pres. 99.985 % >63Cu29 : pres. 69.17 %
The problem with choosing a reaction based on 62Ni28 is that it is less than 4% of the Ni present, so that even if all of it reacted, it wouldn't explain 30% Cu. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/Project.html
