Josh: First, thanks for at least looking at the methodology and then trying to critique it w/o resorting to personal attacks... part of this exercise was to see who can at least think out of the box and consider some PROPOSED line of reasoning. Second, and this really irks the hell out of me because I reread what I've written numerous times to make sure my wording is accurate before posting my msg. Its frustrating when someone responds and it seems as if they just plain didn't see specific words that are essential to the message, so they've really just wasted their time because they really didn't respond to my message as *I* had written it... the only other explanation is that they are so strongly driven to win a debate, or prove that they are more intelligent, that they purposely pick out specific parts of a statement and ignore the rest, and then use the partial information to try to make the other person's argument look wrong... So, if you will please indulge me just a little longer... I'd appreciate it. Let's go over this a step at a time... You stated: "But steam at 100C and 1 atmosphere pressure has a density of 0.6 kg / m^3. It can't be 10 g/m^3." I thought it would have been clear by how I worded it, but apparently not, so let me be perfectly clear; I was NOT saying that the output vapor content was 10g/m^3. I specifically state in step#1: " ***can't remember*** but say its 10g/sec" The inlet water flow rate has varied for each demo, so I wasn't referring to an actual flow rate. All I was trying to establish in this step was that we know the mass of water going in... WHATEVER IT IS... so forget I even mentioned the 10g/sec for now... let's just go with this and see where it leads. Do you see the very first word in step #2??? "ASSUME" It means just that... for this scenario, just accept that all the mass of incoming water is vaporized. I'm not asking you to admit that that is what's really happening, so relax and follow the reasoning... There is only one inlet and one outlet on this 'box', so the mass of water in MUST equal the total mass of water out, in whatever forms (i.e., liquid + vapor), **IF** the pressure does not start to build up inside the box! In fact, since a small volume of liquid water expands into a very large volume of vapor, the pressure would build up quite rapidly if the vapor cannot escape from the box fast enough... but from what Galantini said, he has measured the temp/pressure/RH ***tens of times*** and the pressure is always ambient and temp is always > 100.1C. And for gawd's sake, let's assume for this moment that his instrument is accurate. So, taking into consideration the assumptions and caveats noted, can we agree that steps 1 to 4 get us to this: =============================== Total mass in = total mass out *IF* pressure does not increase inside the box =============================== Let's stop there for tonight as I need to get some rest... we'll pick-up the step-by-step analysis tomorrow or monday.
-Mark
