Josh: Your off by a factor of 1000 on the saturation mass of water vapor at 100.1 and 1 atm... So I'll assume that your calc was in kg/m^3, and you forgot to convert to grams... NIST has a really nice website for calculating physical properties here: http://webbook.nist.gov/chemistry/fluid/ >From that site, and plugging in 1.013 bar 100.1C we get a density of 0.597 KILOgrams/m^3:
Temp(C) Pres(bar) Dens(kg/m3) Vol(m3/kg) Phase 100.10 1.0130 0.59729 1.6742 vapor I think your intuitive sense is on vacation :-)... When you calculated .6g/m^3 as the maximum mass of water in a cubic meter volume, your intuitive sense should have thrown up a red flag and said, "Geez, 0.6 grams is only a few drops at most, and knowing that air can hold more water as temperature goes up, and we're at 100C, I'd think that it could hold much more than a few drops of water." So, given the correct fact that the maximum mass of water in vapor form at 100.1 and 1013 mbar is 600g/m^3 -- this is WAY MORE than the flow rate I was using. So please re-evaluate steps 1 to 4 of the methodology given the correct figures... -Mark
