Ransom Wuller, an attorney who hangs out on Ecatnews.com, asked me to ...
well here's what he said:

"Oh and Maryyugo, you can do Lewan's second test really easy, take a hose,
run 11 liters of water through it into a 6 liter bucket and let me know if
your floor gets wet, if so you just proved Rossi had O/I of greater then
3/1. Or do you have the audacity to disagree."

I didn't recall which test that was and Wuller provided this link:

http://www.nyteknik.se/incoming/article3166569.ece/BINARY/Report+test+of+E-cat+28+April+2011.pdf

I guess Wuller's theory is that if 5 liters of water disappear, they must
end up as steam.  And if they do, the energy from the heat of vaporization
of that water (plus the heat required to heat the whole volume to boiling)
is 3X more than the input energy measured by Lewan.  Apparently this
experiment was discussed in the English version of NyTeknik here:

http://www.nyteknik.se/nyheter/energi_miljo/energi/article3166552.ece

I have to admit, I can't follow the PDF report enough to figure out what
reservoir 1 and 2 are and what volumes Lewan is measuring.    And even if
Lewan lost some water along the way, was it necessarily converted to
steam?

I also notice that Lewan was shown two "naked" E-cats and that the one used
for the experiment was completely wrapped in what is presumed to be thick
insulation.  Far as I know, however, that E-cat was never unwrapped to show
it was the same as the others.  I'm not sure if that matters but it does
leave another unknown.  Maybe that E-cat was quite different as in larger
than the bare ones and as in "had some chemical or stored energy source in
it".

So let's see if I understand the claim:  11 liters of water were supplied
and 6 were recovered.  5 are unaccounted for and presumed to be steam.
But I see that Lewan claimed more than twice that, 11160 grams, as the mass
of water evaporated.  If I read him right.  So where does Wuller's 5 liters
come from?  Is there another experiment?  I'll ask him even though he's
sort of abrasive in emails.  I guess he's convinced Rossi's machine is real
and he doesn't like to be questioned. I wish he'd just participate in the
discussion but the question is interesting so I reposted it here.

Lewan's calculation of total energy required to vaporize the water seems
fine if one assumes it was all vaporized.  I don't know how he knew it
was.  I tried to backtrack through the PDF paper and I get confused about
what was done.

Anyone know what really happened there or shall I inquire directly of
Lewan?  I believe he doesn't always follow this list but he does respond to
emails.  Or can someone point to what I'm missing?

I didn't slog through the video but I guess I will when I have time.  Maybe
he explains it better there.

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