I took a table of nuclides and performed a Energy difference between the
different nickel isotopes, plus associated proton and electron, and the
daughter copper isotopes and compared the net released energy to the energy
required to overcome the coulomb barrier. The most significant energy release
which exceeds the barrier occurs when the Ni62 or Ni64 isotopes are converted.
The delayed beta plus decay which is present for all of the other
transformations looses a large amount of energy to a neutrino which promptly
escapes the device. I will demonstrate the numbers below.
These components are required to build Cu63 from Ni62
1 u = 931.494 MeV Disregard the slight rounding errors, excel chart source of
data
Ni62 Mass=61.92835 (u) Energy=57685.88 MeV
Proton Mass=1.007276 (u) Energy=938.2716 MeV
Electron Mass=.000549 (u) Energy=.510999 MeV
Coulomb Barrier Energy ~5.6 MeV according to Rossi in his paper
Cu63 Mass=62.9296 (u) Energy=58618.54 MeV
Mass of components of Cu63;Ni62 + Proton + Electron=62.936175 (u)
Energy=58624.66 MeV
Mass decrease that must be released as energy=62.936175 - 62.9296 = .006575 (u)
Energy= 6.12457 MeV - 5.6 MeV Barrier = .52457 MeV;Same Calculation for Cu65
yields 1.8532 MeV
In these reactions there are no Beta Plus Decay radiation losses due to
neutrino release and no 511 keV gammas.
Please note that I also calculated the expected energy release due to W&L
process on the isotopes such as Ni60 and had perfect energy correlation when
the energy required to make a neutron from a proton and electron is included.
Exactly the same energy is seen in both paths (Rossi and W&L) when the
starting point is a nickel isotope with a proton and an electron, and the final
point is the next higher isotope of nickel.
I am working very hard to get a clear understanding of the coulomb barrier
energy behavior. I can show that the alpha process within stars stops once
iron has been synthesized, but this is only true if the barrier energy is
trapped within the nucleus in the form of mass. I am approaching the problem
from different directions to prove whether or not this hypothesis is accurate.
Dave
-----Original Message-----
From: pagnucco <[email protected]>
To: vortex-l <[email protected]>
Sent: Mon, Jun 4, 2012 11:49 pm
Subject: Re: [Vo]:about Triumph Management (and LENR)
David,
Can you explain your conclusion.
can't see how any energy is released in these Ni --> Cu transmutations.
Lou Pagnucco
David Roberson wrote:
I may have been a bit to fast in pointing out the possible endothermic
nature of the Ni62 and Ni64 reactions. They actually are the best two
isotopes to use if you were not to rely upon the beta plus decay for a
substantial portion of the energy release. They further are not
susceptible to having the 511 keV gammas that would no doubt be released
by the reactions involving the other nickel isotopes since copper 63 and
65 are stable and do not decay into nickel by that process.
So, if Rossi is actually able to overcome the coulomb barrier by some
mechanism and his device only uses the Ni62 and Ni64 isotopes then it
could be functional. The energy released per atom for these two isotopes
is only 1 or 2 MeV after satisfying the coulomb barrier, but that is a
lot more than any chemical reaction can deliver. I wonder if the
relatively modest amount of energy release also can be more safely
directed toward useful forms such as vibrational coupling into the
surrounding structure.
All of my estimates and calculations assume the reaction path that has
been suggested by Rossi instead of the W&L process which would be much
more energetic. Each of these proposed mechanisms has it's own particular
problems to overcome.
Dave
-----Original Message-----
From: David Roberson <[email protected]>
To: vortex-l <[email protected]>
Sent: Mon, Jun 4, 2012 10:30 am
Subject: Re: [Vo]:about Triumph Management (and LENR)
I just wanted to point out that if Ni62 and Ni64 are the only isotopes
that work then the addition of a proton to either results in the
production of a stable isotope of copper which does not undergo beta plus
decay. Much less energy is released per atom if the beta plus decay is
avoided. My calculations suggest that these two reactions might actually
be endothermic due to the large coulomb barrier.
Perhaps this is a bit of misdirection?
Dave
-----Original Message-----
From: integral.property.service <[email protected]>
To: vortex-l <[email protected]>
Sent: Mon, Jun 4, 2012 9:30 am
Subject: Re: [Vo]:about Triumph Management (and LENR)
A.R. from Florida with love,
"Andrea Rossi
