There are two basic processes going on in cold fusion when it is working
properly: one(1) is charge accumulation that shields the coulomb barrier of
atoms, and two(2), the other is quantum mechanical entanglement of protons
from ionized hydrogen atoms that thermalize the radiation produced by
fusion.


It is possible for one(1) to be active when two(2) is not. This is true in
the LeClair cavatation system where much of the energy produced by the
reaction comes off as Gamma radiation. The LeClair system is very cold and
does not have cracks which will produce entangled protons.


Early on, Rossi had trouble with his 100 gram reactor when it was starting
up and shutting down because it was too cold during those times.


Dr. Kim explains the nuclear energy side of this entanglement mechanism in
this paper:


http://www.physics.purdue.edu/people/faculty/yekim/BECNF-Ni-Hydrogen.pdf


Kim shows how cold fusion of a cooper pair of protons (two protons stuck
together) will produce certain types of nuclear reactions.


In more detail in the old Rossi reactor design, at startup, a large amount
of gamma radiation appears before proton entanglement has established
itself since the temperature of the nickel has not gotten to the relatively
low Curie temperature (nickel has the Curie temperature of 631 K (~358 C)).
Formation of the proton condensate is sensitive to the magnetic nature of
nickel. When nickel is ferromagnetic it won’t let the protons form and join
the proton assemblages.  In such a collection of identical and entangled
protons, all the protons in the collection share in the nuclear energy that
any given member is exposed to.  Nickel must first be made paramagnetic by
heat so that the protons can join the superconductive proton assemblage.
This entanglement process makes the heat output conversion of the cold
fusion reaction possible. Rossi fixed this problem when he added a
secondary heater to his old design to preheat the reactor structure before
the Ni-H reaction begins.



The coherent and entangle wave forms of these many protons that comprise
the proton condensate will all work in concert through a quantum mechanical
wave based summation process to form a combined, entangled and coherent
single de-Broglie wave form. The whole proton condensate then participates
in nuclear fusion. But the proton condensate can be spread out in the
nickel lattice and also in the hydrogen envelope and even inside the walls
of the reaction vessel.  Because of its very large coherent de-Broglie wave
form, the effective quantum mechanical range at which this condensate
operates may be very large, being spread out anywhere up to hundreds of
nano-meters which always include the proton pair that has participated in
the fusion reaction.



It seems to me that when copper or tungsten is used as the lattice
material, the cold temperature problem in the lattice with regard to gamma
production is not as pronounced because of the paramagnetic nature of these
metals.


Superconductivity and ferromagnetism just do not go well together.


To address Francis points, it is at or beyond the cutting edge of condensed
matter physics to determine how the protons behave in the way they do in
the lattice of a transition metal.


But the research of Piantelli has shown that 6 MeV protons are coming out
of the nickel after these bars are immediately removed from the Piantelli
reactor.


This is a solid indicator to me that double proton fusion is occurring in
the nickel lattice. When these bars are removed from the reactor they cool
rapidly. This rapid cooling of these bars takes their temperature quickly
below the Curie temperature of nickel. The energy of the cold fusion
reaction is no longer being thermalized by entanglement of the protons, so
all 6 MeV of the reaction is being produced by the nuclear relaxation
process of the excited nucleus.


Please realize that cold fusion using carbon based SWNT is new. It is
unlike what Rossi originally started out with. And we can only suspect that
he is now using carbon based SWNT from what we see in the NASA patents
(this comes from the assumption that the Navy and NASA talk among
themselves). When SWNT are used, we do not know where the fusion is
occurring, inside the tubes or in the nickel lattice or both. Because we
are going into the unknown experimentally, be careful and check for gamma
radiation at all times. Don’t be caught unawares as LeClair was and spend
any time in a hospital.


Cheers:  Axil


On Mon, Jun 25, 2012 at 6:28 AM, Jojo Jaro <[email protected]> wrote:

> **
> Axil,
>
> In you proposed theory of Charge Accumulation on 1 dimensional SWNTs, you
> propose screening of Coulomb barrier that will result in fusion of H+ with
> H+ or Ni with H+.
>
> In both of these cases, I believe gammas will be produced in abundance.
> Ed Storms' cracks will shield gammas because the reaction is way deep in
> the crevice of the crack.  However if SWNT are the NAE, the fusion will be
> out in the open where the walls will not shield or thermalize the radiation.
>
> In you proposed theory, how is radiation being shielded or should we
> expect copious amounts of hard gammas with  SWNT NAE?
>
>
> Jojo
>
>
>
>

Reply via email to