Ed,
I still think this strange behavior you mention is in violation
of our present definition of COE.. the resonance should dampen out before doing
any useful work if powered by temperature - random motion of atoms.. if you are
saying the tight confinement of the cavity is allowing this random motion to be
"focused" along the linear molecule then you are positing an HUP trap.. Even
the energy sink would be considered a zero point source if it somehow changed
attraction levels after photon emission because it is a quantum effect of the
geometry. I don't disagree with your results but I think you are denying the
underlying cause. I would also posit your photon emission is due to
re-association where the Hydroton atoms briefly disassociate, fall further into
the sink and then immediately reform your molecule emitting a spectrum shifted
photon... similar to Mills hydrino or Jones fractional hydrogen. It is
plausible that these emissions could lower the columb barrier to the point of
fusion but I have to consider photon emission as useful work and don't see the
COE to account for it.
Fran
From: Edmund Storms [mailto:[email protected]]
Sent: Friday, May 31, 2013 9:11 AM
To: [email protected]
Cc: Edmund Storms
Subject: EXTERNAL: Re: [Vo]:Of NAEs and nothingness...
On May 30, 2013, at 11:39 PM, Harry Veeder wrote:
On Thu, May 30, 2013 at 11:00 AM, Edmund Storms
<[email protected]<mailto:[email protected]>> wrote:
Harry, imagine balls held in line by springs. If the end ball is pull away with
a force and let go, a resonance wave will pass down the line. Each ball will
alternately move away and then toward its neighbor. If outside energy is
supplied, this resonance will continue. If not, it will damp out. At this
stage, this is a purely mechanical action that is well understood.
In the case of the Hydroton, the outside energy is temperature. The temperature
creates random vibration of atoms, which is focused along the length of the
molecule. Again, this is normal and well understood behavior.
The strange behavior starts once the nuclei can get within a critical distance
of each other as a result of the resonance. This distance is less than is
possible in any other material because of the high concentration of negative
charge that can exist in this structure and environment. The barrier is not
eliminated. It is only reduced enough to allow the distance to become small
enough so that the two nuclei can "see" and respond. The response is to emit a
photon from each nuclei because this process lowers the energy of the system.
Ed,
With each cycle energy of the system is only lowered if the energy of the
emitted photon is greater than the work done by the "random vibration of atoms"
on the system.
NO Harry! There is no work done by the random vibrations. These are the result
of normal temperature. The photon is emitted from the nucleus and carries with
it the excess mass-energy of the nucleus.
The change is analogous to an exothermic chemical reaction which requires some
activation energy to initiate but the reaction products are in a lower energy
state. Because of the shape of the coulomb "hill" the hill can only be climbed
if the energy emitted increases with each cycle.
No! The hill height is reduced by an intervening negative charge. As a result,
the hill height is reduced so that it can be surmounted by the vibrations
occuring in the Hydroton. Normally, the hill is too high for such small
vibrations to have any effect. The hill is reduced in height as a result of the
Hydroton forming. As a result, it is the unique condition required to make CF
work. All the theories use something similar, but without a clear description.
This is like a ball rolling between two hills. It rolls down the side of one
hill, through the valley and up the other side. In the process, it picks up a
little energy from the surroundings (temperature in this case) to reach the
top, where it throws a switch and turns on a light for a brief time.
Immediately, it starts to roll back down and returns to the first hill where it
again reaches the top and turns on a light for a brief time. This back and
forth continues until the battery powering the light is exhausted and the hills
disappear. The light has no relationship to the motion of the ball. The ball
only throws the switch.
The Hydroton allows the Coulomb barrier to be reduced enough for the nuclei to
respond and emit excess energy. Because the resonance immediately increases the
distance, the ability or need to lose energy is lost before all the extra
energy can be emitted. If the distance did not increased, hot fusion would
result. The distance is again reduced, and another small burst of energy is
emitted. This process continues until ALL energy is emitted and the intervening
electron is sucked into the final product.
In your model, the coulomb barrier appears to be like a hill in a uniform
gravitational field.
Yes, see above
It is possible to climb such a barrier in steps by emitting the same amount of
energy with each cycle, but this barrier does not correspond with the actual
barrier that exists between protons. Climbing a genuine coulomb barrier
requires more energy with each cycle, so that requires more energy be emitted
with each cycle. The extra energy emitted heats the lattice even more and
produces more powerful vibrations of the lattice which can push the protons
even closer together.
No, the Coulomb barrier is slowly reduced in height as mass-energy is lost,
thereby allowing the nuclei to get closer each time the cycle repeats.
Finally, the Coulomb barrier disappears and the two nuclei fuse, but very
little excess mass-energy is present when this happens. Consequently, when the
electron is absorbed, the resulting neutrino has very little energy to carry
away.
I might add, all theories require a similar process. All theories require a
group of hydron be assembled, which requires emission of Gibbs energy. Once
assembled, the fusion process must take place in stages to avoid the hot fusion
result, as happens when the nuclei get close using a muon and without the
ability to limit the process. Unfortunately, the other theories ignore these
requirements.
The proton has nothing to do with the work done at each step. This work comes
from the temperature. The photon results because the assembly has too much
mass-energy for the distance between the nuclei. If the nuclei touched, the
assembly would have 24 MeV of excess mass-energy if they were deuterons. If
they are close but not touching, the stable mass-energy would be less. At a
critical distance short of actually touching, the nuclei can "know" that they
have too much mass energy. How they know this is the magic that CF has revealed.
Here is the magic: they share an electron and it is through this "common
ground" that they know. If they don't share an electron they won't give up any
excess mass-energy until they are touching at which point they give it up all
at once which is what happens in hot fusion.
Yes, good summary.
Ed Storms
Harry
