Fran, I don't know how to explain this process any more clearly. The
resonance is not using energy or emitting energy. It simply occurs as
a result of the ambient energy, i.e. temperature. All chemical
structures vibrate and resonate. This behavior is not visible unless
something happens that can be detected.
The detected photons in this case come from the nucleus, not from the
resonance. They get their energy from the mass-energy of the nucleus.
The resonance ONLlY allows the two nuclei to get close enough to
create a condition that requires release of mass-energy for a brief
time. You keep making the process more complicated than it is. This
is a VERY SIMPLE effect. The only unique aspect is how the nuclei get
information needed to cause the release of photons in order to reduce
their mass energy.
If you want to propose your own theory, that is ok, but please do not
make it part of what I'm proposing. Please try to understand EXACTLY
what I'm proposing before proposing your own ideas.
As this mass-energy is reduced, the Coulomb barrier is lowered
further, permitting the two nuclei to get closer at each cycle. Once
the nuclei fuse, the Hydroton ceases to exist and instead nuclei of D
are present if the original nuclei in the Hydroton were H, the final
nuclei is He if D made the Hydroton, and the final nuclei is tritium
if H+D were in the Hydroton. The He diffuses away while the tritium
and D can enter other Hydrotons that continuously form. This is a
contineous process limited ONLY by how fast the hydrogen isotopes can
get into the gap.
There is no such thing as a Hydroton atom. The Hydroton is a MOLECULE
made up of atoms. Please read what I write carefully so that I do not
have to keep explaining.
Ed Storms
On May 31, 2013, at 8:49 AM, Roarty, Francis X wrote:
Ed,
I still think this strange behavior you mention is
in violation of our present definition of COE.. the resonance should
dampen out before doing any useful work if powered by temperature -
random motion of atoms.. if you are saying the tight confinement of
the cavity is allowing this random motion to be “focused” along the
linear molecule then you are positing an HUP trap.. Even the energy
sink would be considered a zero point source if it somehow changed
attraction levels after photon emission because it is a quantum
effect of the geometry. I don’t disagree with your results but I
think you are denying the underlying cause. I would also posit your
photon emission is due to re-association where the Hydroton atoms
briefly disassociate, fall further into the sink and then
immediately reform your molecule emitting a spectrum shifted photon…
similar to Mills hydrino or Jones fractional hydrogen. It is
plausible that these emissions could lower the columb barrier to the
point of fusion but I have to consider photon emission as useful
work and don’t see the COE to account for it.
Fran
From: Edmund Storms [mailto:[email protected]]
Sent: Friday, May 31, 2013 9:11 AM
To: [email protected]
Cc: Edmund Storms
Subject: EXTERNAL: Re: [Vo]:Of NAEs and nothingness...
On May 30, 2013, at 11:39 PM, Harry Veeder wrote:
On Thu, May 30, 2013 at 11:00 AM, Edmund Storms
<[email protected]> wrote:
Harry, imagine balls held in line by springs. If the end ball is
pull away with a force and let go, a resonance wave will pass down
the line. Each ball will alternately move away and then toward its
neighbor. If outside energy is supplied, this resonance will
continue. If not, it will damp out. At this stage, this is a purely
mechanical action that is well understood.
In the case of the Hydroton, the outside energy is temperature. The
temperature creates random vibration of atoms, which is focused
along the length of the molecule. Again, this is normal and well
understood behavior.
The strange behavior starts once the nuclei can get within a
critical distance of each other as a result of the resonance. This
distance is less than is possible in any other material because of
the high concentration of negative charge that can exist in this
structure and environment. The barrier is not eliminated. It is only
reduced enough to allow the distance to become small enough so that
the two nuclei can "see" and respond. The response is to emit a
photon from each nuclei because this process lowers the energy of
the system.
Ed,
With each cycle energy of the system is only lowered if the energy
of the emitted photon is greater than the work done by the "random
vibration of atoms" on the system.
NO Harry! There is no work done by the random vibrations. These are
the result of normal temperature. The photon is emitted from the
nucleus and carries with it the excess mass-energy of the nucleus.
The change is analogous to an exothermic chemical reaction which
requires some activation energy to initiate but the reaction
products are in a lower energy state. Because of the shape of the
coulomb "hill" the hill can only be climbed if the energy emitted
increases with each cycle.
No! The hill height is reduced by an intervening negative charge. As
a result, the hill height is reduced so that it can be surmounted by
the vibrations occuring in the Hydroton. Normally, the hill is too
high for such small vibrations to have any effect. The hill is
reduced in height as a result of the Hydroton forming. As a result,
it is the unique condition required to make CF work. All the
theories use something similar, but without a clear description.
This is like a ball rolling between two hills. It rolls down the
side of one hill, through the valley and up the other side. In the
process, it picks up a little energy from the surroundings
(temperature in this case) to reach the top, where it throws a
switch and turns on a light for a brief time. Immediately, it starts
to roll back down and returns to the first hill where it again
reaches the top and turns on a light for a brief time. This back and
forth continues until the battery powering the light is exhausted
and the hills disappear. The light has no relationship to the
motion of the ball. The ball only throws the switch.
The Hydroton allows the Coulomb barrier to be reduced enough for the
nuclei to respond and emit excess energy. Because the resonance
immediately increases the distance, the ability or need to lose
energy is lost before all the extra energy can be emitted. If the
distance did not increased, hot fusion would result. The distance is
again reduced, and another small burst of energy is emitted. This
process continues until ALL energy is emitted and the intervening
electron is sucked into the final product.
In your model, the coulomb barrier appears to be like a hill in a
uniform gravitational field.
Yes, see above
It is possible to climb such a barrier in steps by emitting the same
amount of energy with each cycle, but this barrier does not
correspond with the actual barrier that exists between protons.
Climbing a genuine coulomb barrier requires more energy with each
cycle, so that requires more energy be emitted with each cycle. The
extra energy emitted heats the lattice even more and produces more
powerful vibrations of the lattice which can push the protons even
closer together.
No, the Coulomb barrier is slowly reduced in height as mass-energy
is lost, thereby allowing the nuclei to get closer each time the
cycle repeats. Finally, the Coulomb barrier disappears and the two
nuclei fuse, but very little excess mass-energy is present when this
happens. Consequently, when the electron is absorbed, the resulting
neutrino has very little energy to carry away.
I might add, all theories require a similar process. All theories
require a group of hydron be assembled, which requires emission of
Gibbs energy. Once assembled, the fusion process must take place in
stages to avoid the hot fusion result, as happens when the nuclei
get close using a muon and without the ability to limit the process.
Unfortunately, the other theories ignore these requirements.
The proton has nothing to do with the work done at each step. This
work comes from the temperature. The photon results because the
assembly has too much mass-energy for the distance between the
nuclei. If the nuclei touched, the assembly would have 24 MeV of
excess mass-energy if they were deuterons. If they are close but
not touching, the stable mass-energy would be less. At a critical
distance short of actually touching, the nuclei can "know" that they
have too much mass energy. How they know this is the magic that CF
has revealed.
Here is the magic: they share an electron and it is through this
"common ground" that they know. If they don't share an electron they
won't give up any excess mass-energy until they are touching at
which point they give it up all at once which is what happens in hot
fusion.
Yes, good summary.
Ed Storms
Harry
