I guess one of the reasons I just don't get the Rydberg atom hypothesis, is
that mainly has to do with the electron orbitals and not the nuclear state.
  That's my understanding at least.  Perhaps Kim's paper will enlighten how
the nuclei interact to show a strong interaction;  one that follows E=mc^2.
 I have a lot of respect for Kim and he always is enlightening   I suppose
that I need to understand the Rydberg stuff a little more before jumping to
conclusions; (for example the inverse-Rydberg atoms sound very much like
hydrinos or pseudo-neutrons ).

But all  that is hypothetical.   The evidence so far, based on the design,
is it hot and appears to be a plasma in metal.  This is where a full
accounting of all possible interactions would be enlightening.

Then there are the reports of the 1.5 Tesla magnetic fields.  I wish there
was a magnetometer in the public demonstration that showed that.  1 Tesla
is HUGE!   Most superconducting MRI magnets only reach 1T.
(5T is pretty extreme).  I walked past a 1.5T MRI machine accidentally with
an inkpen in my pocket.  From 10ft away, the magnet was lifting the pin out
of my pocket (upon which I realized I could quench the magnet, and so I
left the room clutching onto my pen).  If the Defkcalion reactor produces
that kind of field in the small space, it might be possible, but it's
another question mark.

Eric, I would say you have a very good superfecta there (in horse racing
thats picking 1 2 3 & 4).  Primarily I think
2 and 4.  2 from low energy reactions and 4 from recoil atoms caused by 3,
2 and 1.  But that is pure hot fusion. With the intervening metal lattice,
that may not be the case precisely.

Best Regards..









On Tue, Jul 30, 2013 at 11:21 PM, Eric Walker <[email protected]> wrote:

> On Tue, Jul 30, 2013 at 8:19 PM, Eric Walker <[email protected]>wrote:
>
>>
>>    1. p+p -> p+p "reversible" fusion, along the lines of Jones's
>>    hypothesis.
>>    2. p+e+p -> d, along the lines of Ed's hypothesis.
>>    3. p+d -> 3He + Q (5.5 MeV) (my own favorite)
>>    4. p+Ni -> Cu (as suggested by Rossi a long time ago, and which no
>>    one really likes).
>>
>> I'm betting on (2), somewhere beneath the surface.
>>
>
> Typo -- I'm betting on (3).
>
> Eric
>
>

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