It is interesting to do a little math around this experiment. Presume that the popper is operating with a fuel of 1 microliter of water and produces a net excess energy of 1000 joules. Presume Mills to be correct in assigning most of the reaction is conversion to 1/4 hydrino state that is liberating ~54 eV per atom (8.65E-18 J). Then to get 1000 J of excess heat, would require the transition to 1/4 hydrino state of 1.16E20 H atoms. A mole is 6.02E23, so getting the 1000 J would take (1.16E20 H atoms)/(6.02E23 atoms per mole) = 1.9E-4 mole. For H, one mole is 1 gram, so getting 1000 J consumed 190 micrograms of H.
In H2O, Hydrogen is 2/18 or 1/9 of the molecule. So, 1 microliter of water is 1 mg of water and has 1/9 of 1 mg of H = .111 mg of H = 111 micrograms of H. Hmmm. So 190 micrograms of H was converted to 1/4 Hydrino state, but only 111 micrograms of H was present to start. So, if the reaction was 100% efficient, it would require almost 2 microliters of water to begin. Or, the H atoms would have to be sent to a smaller fraction hydrino state liberating more energy per atom of H converted. This seems too efficient in conversion of H to hydrino, or much more energy is being liberated per atom of H. Is my math correct? Bob On Mon, Feb 3, 2014 at 2:14 PM, Nigel Dyer <l...@thedyers.org.uk> wrote: > > http://www.blacklightpower.com/whats-new/ > >
