Bob, As far as I know, there is no external magnetic field applied to the reactor by means of coils. Anyway, the H field might become from the lattice itself? Rossi and DGT have said to measure huge magnetic field near the reactor. Always difficult to know what is the cause and what is the result of an unknown black box.
Arnaud -----Original Message----- From: Bob Cook [mailto:frobertc...@hotmail.com] Sent: mardi 18 février 2014 22:04 To: vortex-l@eskimo.com Subject: [Vo]:Re: The Rossi effect as an Inverted Mossbauer Effect Importance: High Amaud and Jones-- Keep in mind that at least for magnetic coupling--spin/angular momentum and its associated energy-- it is possible to modify resonant energy levels of the QM system by changing the magnitude of the static H field. Transitions between J spin states can be created to match the necessary energy to make a nuclear transition probable. Bob Cook -----Original Message----- From: Arnaud Kodeck Sent: Tuesday, February 18, 2014 7:56 AM To: vortex-l@eskimo.com Subject: RE: [Vo]:Re: The Rossi effect as an Inverted Mossbauer Effect Ni61 is the only odd isotope of Ni and count only for 1% of the natural Nickel. It will be huge cost to "enrich" the Ni61. Ni61 + p => Cu62 which is beta+ emitter which would be easy detected in positron/electron annihilation. I don't think this is the reaction which happends inside Rossi's reactor. The debye temperature is around 180°C for the nickel. Above this temperature, phonon can move freely in the lattice at the speed of sound. Axil always keeps speaking of coupling phonon/photon (polariton) at same resonant frequency could make the lattice to oscillate. If excitation frequency (photon) matches the resonant frequency of the lattice (phonon), wouldn't be like an invertedmossbauer effect? Just thoughts ... On 2014-02-18 15:53, Jones Beene wrote: > From: Arnaud Kodeck > > From DGT, we know that the nickel needs to be above the debye > temperature for the Rossi effect to take place. Vibration in the lattice > is > a key element. The Mossbauer effect could be the excitation needed for the > vibration in the lattice to take place. > > Jones, can you explain what do you mean by Mossbauer isotope? > > Arnaud, > > First, off - I am not an expert in NMR and that is why I have been > quizzing > Bob Cook about a subject that came up as far back as 1990 - in an effort > to > explain the excess energy of LENR - and the lack of detectability of gamma > radiation. > > Generally speaking, an isotope - usually with odd numbered amu such as > iron-57 or nickel-61, can permit a limited kind of "photon chain reaction" > of moderate energy photons due to a loss-free (recoilless) > absorption/emission nuclear property, and this would be especially true > within an "exciton" of the host metal. > > I'm guessing that since the role of 57Fe is well-known in spectroscopy, > you > are really asking how a corresponding nickel isotope nickel participates > in > a similar reaction, where we are interested in bulk energy effects and not > subtle physical effects which are illuminated by the coherence. > > That bulk effect, if it exists - would be the "inverted" reaction. Of > course, the reaction must involve photons below the detection limit - > since > no gamma is detected. It would also probably need to involve infrared > coherence, and the idea is that in an inverted reaction there can be > frequency upshifting so two widely separated spectra are locked in phase. > > In nickel at 350 degrees C, the nuclei will be moving chaotically due to > thermal motion, but not as chaotically if there is IR coherence > (superradiance) at near 10 THz. This part has actually been detected by > NASA > but not the rest of the hypothesis. A moderate energy photon, of the > Mossbauer type - but below the detection limit of about 4 keV interacts > with, or is emitted by a nucleus which has a spread of vibrational values, > and there is a the Doppler effect. This photon can be called a gamma ray, > since it is of nuclear origin, but because the energy level must be low to > avoid detection - the terminology is x-ray. This is all hypothetical of > course. > > Problem is: and may you realize this - the known value for nickel-61 of a > resonant photon is 67.4 keV which would have been detected in the Rossi > experiment. Therefore either there is either a second active Mossbauer > isotope, or a lower level resonance, below the detectability level. Of > more > likely - the inverted Mossbauer effect is a fiction. > > Anyway, to produce a resonant third signal, the two energies - the main > x-ray photon and Doppler shifted photon need to overlap at the IR > resonance > (this signal will be in the range of FIR - far infrared at about 5-30 > THz). > Thus a putative inverted system would be in limited photon/phonon > coherence > and possess a limited photon/phonon chain reaction capability at some > level > which is not detectable by normal Geiger/radiation meters. > > To backtrack, what Mössbauer discovered is that when the atoms are within > a > solid matrix the effective mass of the nucleus is very much greater. The > recoiling mass is now effectively the mass of the whole system and if the > photon energy is small enough the recoil of the nucleus is too low to be > transmitted as a phonon and so the whole system recoils as if it were > coherent and it can be actually coherent in the IR range if the blackbody > peak is narrowed. > > In the inverted version, presumably the resonance will allow FIR energy to > resonate as if the whole system were coherent and this will be upshifted > to > a level felt by the nucleus (low keV). However, to my thinking this does > not > work at 67.4 keV so the whole theory falls apart. > > As you will notice, this suggestion has not been well-vetted - even after > 24 > years, so take it for what it's worth. > > Jones -- Arnaud Kodeck LAKOCO Sprl
