*Ni-62 removal would be expensive for Rossi* Rossi says that Ni62 enrichment gives him better performance. IMHO, all fusing nuclei input to the LENR reaction must have zero spin.
All isotopes of Cu have non zero spins and therefore are non reactive in LENR fusion. Cu will produce RF as being NMR active. On Wed, Sep 10, 2014 at 1:14 AM, Bob Cook <frobertc...@hotmail.com> wrote: > Eric-- > > I do not think the reaction of the d,p variety occurs. There are not > 87,000 Ev gammas reported, which would be evident as you suggest. I do not > think Ni-63 is involved in the production of Cu-63. Ni-62 removal would be > expensive for Rossi. > > Bob > > > ----- Original Message ----- > *From:* Eric Walker <eric.wal...@gmail.com> > *To:* vortex-l@eskimo.com > *Sent:* Tuesday, September 09, 2014 8:56 PM > *Subject:* Re: [Vo]:Rossi on Ni62 > > On Tue, Sep 9, 2014 at 6:14 PM, Bob Cook <frobertc...@hotmail.com> wrote: > > I wonder if the new Cu is Cu-63? Rossi may be implying that Ni-62 goes to >> Cu-63, both of which are stable isotopes. Spin coupling to get rid of the >> 6.22Mev of excess mass may be the answer--there are no gammas apparently. >> > > In a 62Ni(d,p)63Ni reaction, the 63Ni will beta- decay to 63Cu. The > proton will have ~ 5 MeV and will excite 11 keV electrons, which can easily > be shielded. There will be a delayed gamma emission after the beta- decay > of Q=87 keV, however, which will not be fully shielded even by 1cm of lead. > If there is vigorous deuteron stripping, there will be a lot of motivation > to remove 62Ni from the nickel. > > Eric > > >
