The forces involved in LENR will disrupt the orbits of electrons and
therefore will make spin coupling unlikely.

On the way to a fusion event, at some point, all the electrons orbiting the
nucleus will be striped and just the nuclei  will participate in the fusion
reaction remain. I believe in an energetic fusion reaction in which all the
electrons that were orbiting the associated nuclei are displaced at a
distance from the reaction.

Furthermore, there is a intense resonant dipole motion that powers the
fusion event and  that underpins and is inherent to a energetic fusion
event. The orbiting electrons cannot transfer there angular momentum to the
nucleus because their orbits have been  totally disrupted.

Most electrons disappear; they have been converted into bosons by
entanglement with photons and reside in polariton solitons.

On Wed, Sep 10, 2014 at 3:27 AM, Bob Cook <[email protected]> wrote:

>  Axil--
>
> You have stated:
>
> <<<<"IMHO, all fusing nuclei input to the LENR reaction must have zero
> spin.
>
> <<<<All isotopes of Cu have non zero spins and therefore are non reactive
> in LENR fusion. Cu will produce RF as being NMR active."
>
> Why do you think non-zero spin isotopes of Ni and Cu are LENR inactive
> and/or fusing nuclei input to the LENR reaction must have zero spin.?
>
> I think that if spin coupling occurs, spin and its angular momentum can be
> swapped among all coupled particles.  However, it must be conserved IMHO.
> I can imagine that  2 Ni isotopes of Ni could change the sign of their spin
> in a magnetic field and pair up as a Cooper pair, much like electrons and
> protons pair up with spin in opposite directions.  The net spin and angular
> momentum would be zero.  Such a pair may react readily with other paired
> particles, for example, paired  H or D particles.  LENR is not fully
> understood yet.
>
> Bob
>
> ----- Original Message -----
> *From:* Axil Axil <[email protected]>
> *To:* vortex-l <[email protected]>
> *Sent:* Wednesday, September 10, 2014 12:07 AM
> *Subject:* Re: [Vo]:Rossi on Ni62
>
> Ni61 has be found to be LENR inactive due to its non zero nuclear spin.
>
> On Wed, Sep 10, 2014 at 3:03 AM, Bob Cook <[email protected]> wrote:
>
>>  Eric--
>>
>> Whoever wrote the Wikipedia item you reference does not appear to
>> understand the difference between spin of 3/2+ and 3/2-.  The statement
>> about the spin of Ni-61 is incorrect.
>>
>>
>> Bob
>>
>> ----- Original Message -----
>> *From:* Eric Walker <[email protected]>
>> *To:* [email protected]
>> *Sent:* Tuesday, September 09, 2014 11:30 PM
>> *Subject:* Re: [Vo]:Rossi on Ni62
>>
>>   I wrote:
>>
>>  About the beta-delayed gamma -- it's not clear that the 63Ni* gamma
>>> decay is a beta-delayed gamma in this instance (see the decay in [1]).  But
>>> as you know beta-delayed gammas are a frequent occurrence.  The half-life
>>> of the beta decay in this case is 100 years, so if there is beta-delayed
>>> gamma emission, the activity would be significant.
>>>
>>
>> The excited state after a beta- decay would be in the daughter (63Cu) not
>> the parent (63Ni).  I don't see any evidence for a 63Cu* excited state.
>>  You are probably right.  Embarrassing rookie error on my part.
>>
>> Eric
>>
>>
>

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