Hey Denis

In my approach, first I fix one water molecule and go radially outward by
binning. In one bin, I calculate average radial force on the water molecule.
( sum of forces on all molecules/no. of molecules in the bin). I access this
force by GROMACS data structure fr.f[indx_atm], which I guess gives the *force
on the atom due to all the atoms in the system.  *

Similar calculations are done for the all other molecules taken as reference
and then average is computed over number of frames and number of molecules.

I am guessing, taking fr.f[indx_atm] as a force acting on molecules is not
right way of computing two-body PMF. Because it contains contributions from
molecules other than reference molecule.

thanks
sikandar
On Sat, Oct 9, 2010 at 2:37 PM, Denis Andrienko <[email protected]>wrote:

> Hi Sikandar,
>
> The situation is a bit more complicated when you have a multicomponent
> mixture (e.g. solute/solvent). If the concentration of solute
> molecules is small, you can integrate out solvent degrees of freedom
> by calculating solute-solute PMF using the pull code. In this case the
> two-body PMF is exactly -log(g_solute(r)) (thought you cannot directly
> calculate it).  The trick is that, at small concentrations, two-body
> solute-solute PMF equals to the coarse-grained interaction potential.
> Hence, people use this two-body PMF to do coarse-grained simulations.
> It is of course incorrect for high concentrations of solute molecules.
>
> I also understand what you do to calculate PMF for water. I think it
> can be done this way, but one has to be very careful about what forces
> to include and how to normalize forces in the bin. Do you take into
> account different number of molecules in bins? In other words, do you
> weight your average by g(r)? Is this an average force from all
> molecules or only from the one which is chosen to be a reference?
>
> Best,
> Denis
>
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