you need to take into consideration what changes between the web2py
environment and the cherrypy one.
assuming that you start cherrypy with something like this in a
mywebserver.py
import cherrypyclass HelloWorld(object):
def index(self):
return "Hello World!"
index.exposed = True
cherrypy.quickstart(HelloWorld())
and do python mywebserver.py to start it, a very few things change between
that process and the one you get doing
web2py.py -a yourpassword
with your app.
are you starting web2py this way or is it "mounted" under apache ?
On Monday, April 1, 2013 5:08:42 AM UTC+2, The Organisation of Secret
Shoppers wrote:
>
> I see... but how should i close the serial port opened by another
> application? does shutting down the whole system close it? initially, i
> created a normal python script just to communicate with the device through
> the serial port. it succeeded. so i moved on to web2py but perhaps i missed
> out something or use the wrong coding which led me to that error. i'm not
> really sure where should i put things but i created a new def "test"
> function and a default/test.html...
>
> attached is the w2p packed file.
>
> without doing anything to the python script, i installed cherrypy and
> wrote a simple web app to test the communication and it worked. so i doubt
> may be there is something wrong in my coding somewhere. :( i have added the
> user to the dialout group too.
>
> sudo usermod -a -G dialout pi
> sudo usermod -a -G dialout www-data
>
> the result is still the same...
>
>
>
>
>
>
> On Sat, Mar 30, 2013 at 6:52 AM, Rufus <[email protected]
> <javascript:>>wrote:
>
>> Perhaps it is already open by another process?
>>
>> I'm not a major linux user (yet) but in windows only one process can open
>> the serial port at a time. Perhaps
>> "Permission denied" is the same as "In use".
>>
>> Also make sure you close it when, if your application doesn't terminate,
>> as web2py doesn't, depending where
>> and how you opened it.
>>
>>
>>
>>
>> On Thursday, March 28, 2013 4:54:29 AM UTC-4, [email protected] wrote:
>>
>>> Hello everyone.
>>> I would like to use web2py as my Raspberry Pi webserver. i need to send
>>> some serial data from the web application to Raspberry Pi and send to a
>>> device. However, i encountered the error of " <class ‘serial.serialutil.
>>> **SerialException’> could not open port /dev/ttyAMA0: [Errno 13]
>>> Permission denied: ‘/dev/ttyAMA0′ "
>>>
>>> I have been stuck at this for weeks and i can't seem to find any
>>> solution except moving on to using cherrypy and jquery. :( but i really
>>> wish to use web2py!
>>>
>>> So, i have this code below that could work fine using normal python
>>> script as well as cherrypy. in web2py, i put this under "default.py" and
>>> create a new def for it.
>>>
>>> import serial
>>> import time
>>>
>>> serialport= serial.Serial ("/dev/ttyAMA0", 9600, timeout=0.5)
>>> serialport.write("\x03LI1234\**x0D")
>>> response=serialport.readlines(**1)
>>> print response
>>> time.sleep(1)
>>>
>>> what could have been done wrongly? :(
>>>
>>> Read more details here: http://yvonnezoe.wordpress.**
>>> com/2013/03/14/web2py-web-app-**progress/
>>>
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