my web2py is forever "on". when i switch on my Raspberry-Pi, the web2py
server is alive and i can access the webpage from another comp in the same
network.
Btw, thank you so much for your patience and help. :) It seems to work
suddenly which i still could not figure out why! :/
just that i'm still stuck at mapping URL, writing arguments and things like
that. Is there any site with good complete examples? i couldn't digest the
web2py manual without matching examples :(


On Mon, Apr 1, 2013 at 4:28 PM, Niphlod <[email protected]> wrote:

> you need to take into consideration what changes between the web2py
> environment and the cherrypy one.
> assuming that you start cherrypy with something like this in a
> mywebserver.py
>
> import cherrypyclass HelloWorld(object):
>     def index(self):
>         return "Hello World!"
>     index.exposed = True
>
> cherrypy.quickstart(HelloWorld())
>
>
> and do python mywebserver.py to start it, a very few things change between
> that process and the one you get doing
> web2py.py -a yourpassword
>
> with your app.
> are you starting web2py this way or is it "mounted" under apache ?
>
>
> On Monday, April 1, 2013 5:08:42 AM UTC+2, The Organisation of Secret
> Shoppers wrote:
>
>> I see... but how should i close the serial port opened by another
>> application? does shutting down the whole system close it? initially, i
>> created a normal python script just to communicate with the device through
>> the serial port. it succeeded. so i moved on to web2py but perhaps i missed
>> out something or use the wrong coding which led me to that error. i'm not
>> really sure where should i put things but i created a new def "test"
>> function and a default/test.html...
>>
>> attached is the w2p packed file.
>>
>> without doing anything to the python script, i installed cherrypy and
>> wrote a simple web app to test the communication and it worked. so i doubt
>> may be there is something wrong in my coding somewhere. :( i have added the
>> user to the dialout group too.
>>
>> sudo usermod -a -G dialout pi
>> sudo usermod -a -G dialout www-data
>>
>> the result is still the same...
>>
>>
>>
>>
>>
>>
>> On Sat, Mar 30, 2013 at 6:52 AM, Rufus <[email protected]> wrote:
>>
>>> Perhaps it is already open by another process?
>>>
>>> I'm not a major linux user (yet) but in windows only one process can
>>> open the serial port at a time.  Perhaps
>>> "Permission denied" is the same as "In use".
>>>
>>> Also make sure you close it when, if your application doesn't terminate,
>>> as web2py doesn't, depending where
>>> and how you opened it.
>>>
>>>
>>>
>>>
>>> On Thursday, March 28, 2013 4:54:29 AM UTC-4, [email protected]:
>>>
>>>> Hello everyone.
>>>> I would like to use web2py as my Raspberry Pi webserver. i need to send
>>>> some serial data from the web application to Raspberry Pi and send to a
>>>> device. However, i encountered the error of " <class ‘serial.serialutil.
>>>> **SerialExcep**tion’> could not open port /dev/ttyAMA0: [Errno 13]
>>>> Permission denied: ‘/dev/ttyAMA0′ "
>>>>
>>>> I have been stuck at this for weeks and i can't seem to find any
>>>> solution except moving on to using cherrypy and jquery. :( but i really
>>>> wish to use web2py!
>>>>
>>>> So, i have this code below that could work fine using normal python
>>>> script as well as cherrypy. in web2py, i put this under "default.py" and
>>>> create a new def for it.
>>>>
>>>> import serial
>>>> import time
>>>>
>>>> serialport= serial.Serial ("/dev/ttyAMA0", 9600, timeout=0.5)
>>>> serialport.write("\x03LI1234\**x**0D")
>>>> response=serialport.readlines(****1)
>>>> print response
>>>> time.sleep(1)
>>>>
>>>> what could have been done wrongly? :(
>>>>
>>>> Read more details here: http://yvonnezoe.wordpress.**com**
>>>> /2013/03/14/web2py-web-app-**pro**gress/
>>>>
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