clearly it was due to a permission problem.... btw, if you don't need apache for anything else, given that the raspberry has "limited" resources it would be better to stick with web2py's "embedded" webserver rather than having it mounted on apache.
On Monday, April 1, 2013 10:56:03 AM UTC+2, The Organisation of Secret Shoppers wrote: > > my web2py is forever "on". when i switch on my Raspberry-Pi, the web2py > server is alive and i can access the webpage from another comp in the same > network. > Btw, thank you so much for your patience and help. :) It seems to work > suddenly which i still could not figure out why! :/ > just that i'm still stuck at mapping URL, writing arguments and things > like that. Is there any site with good complete examples? i couldn't digest > the web2py manual without matching examples :( > > > On Mon, Apr 1, 2013 at 4:28 PM, Niphlod <[email protected] <javascript:>>wrote: > >> you need to take into consideration what changes between the web2py >> environment and the cherrypy one. >> assuming that you start cherrypy with something like this in a >> mywebserver.py >> >> import cherrypyclass HelloWorld(object): >> def index(self): >> return "Hello World!" >> index.exposed = True >> >> cherrypy.quickstart(HelloWorld()) >> >> >> and do python mywebserver.py to start it, a very few things change >> between that process and the one you get doing >> web2py.py -a yourpassword >> >> with your app. >> are you starting web2py this way or is it "mounted" under apache ? >> >> >> On Monday, April 1, 2013 5:08:42 AM UTC+2, The Organisation of Secret >> Shoppers wrote: >> >>> I see... but how should i close the serial port opened by another >>> application? does shutting down the whole system close it? initially, i >>> created a normal python script just to communicate with the device through >>> the serial port. it succeeded. so i moved on to web2py but perhaps i missed >>> out something or use the wrong coding which led me to that error. i'm not >>> really sure where should i put things but i created a new def "test" >>> function and a default/test.html... >>> >>> attached is the w2p packed file. >>> >>> without doing anything to the python script, i installed cherrypy and >>> wrote a simple web app to test the communication and it worked. so i doubt >>> may be there is something wrong in my coding somewhere. :( i have added the >>> user to the dialout group too. >>> >>> sudo usermod -a -G dialout pi >>> sudo usermod -a -G dialout www-data >>> >>> the result is still the same... >>> >>> >>> >>> >>> >>> >>> On Sat, Mar 30, 2013 at 6:52 AM, Rufus <[email protected]> wrote: >>> >>>> Perhaps it is already open by another process? >>>> >>>> I'm not a major linux user (yet) but in windows only one process can >>>> open the serial port at a time. Perhaps >>>> "Permission denied" is the same as "In use". >>>> >>>> Also make sure you close it when, if your application doesn't >>>> terminate, as web2py doesn't, depending where >>>> and how you opened it. >>>> >>>> >>>> >>>> >>>> On Thursday, March 28, 2013 4:54:29 AM UTC-4, [email protected]: >>>> >>>>> Hello everyone. >>>>> I would like to use web2py as my Raspberry Pi webserver. i need to >>>>> send some serial data from the web application to Raspberry Pi and send >>>>> to >>>>> a device. However, i encountered the error of " <class ‘serial.serialutil. >>>>> **SerialExcep**tion’> could not open port /dev/ttyAMA0: [Errno 13] >>>>> Permission denied: ‘/dev/ttyAMA0′ " >>>>> >>>>> I have been stuck at this for weeks and i can't seem to find any >>>>> solution except moving on to using cherrypy and jquery. :( but i really >>>>> wish to use web2py! >>>>> >>>>> So, i have this code below that could work fine using normal python >>>>> script as well as cherrypy. in web2py, i put this under "default.py" and >>>>> create a new def for it. >>>>> >>>>> import serial >>>>> import time >>>>> >>>>> serialport= serial.Serial ("/dev/ttyAMA0", 9600, timeout=0.5) >>>>> serialport.write("\x03LI1234\**x**0D") >>>>> response=serialport.readlines(****1) >>>>> print response >>>>> time.sleep(1) >>>>> >>>>> what could have been done wrongly? :( >>>>> >>>>> Read more details here: http://yvonnezoe.wordpress.**com** >>>>> /2013/03/14/web2py-web-app-**pro**gress/ >>>>> >>>> -- >>>> >>>> --- >>>> You received this message because you are subscribed to a topic in the >>>> Google Groups "web2py-users" group. >>>> To unsubscribe from this topic, visit https://groups.google.com/d/** >>>> topic/web2py/8eBuyKi3uf8/**unsubscribe?hl=en<https://groups.google.com/d/topic/web2py/8eBuyKi3uf8/unsubscribe?hl=en> >>>> . >>>> To unsubscribe from this group and all its topics, send an email to >>>> web2py+un...@**googlegroups.com. >>>> >>>> For more options, visit >>>> https://groups.google.com/**groups/opt_out<https://groups.google.com/groups/opt_out> >>>> . >>>> >>>> >>>> >>> >>> -- >> >> --- >> You received this message because you are subscribed to a topic in the >> Google Groups "web2py-users" group. >> To unsubscribe from this topic, visit >> https://groups.google.com/d/topic/web2py/8eBuyKi3uf8/unsubscribe?hl=en. >> To unsubscribe from this group and all its topics, send an email to >> [email protected] <javascript:>. >> For more options, visit https://groups.google.com/groups/opt_out. >> >> >> > > -- --- You received this message because you are subscribed to the Google Groups "web2py-users" group. 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