You said you notice this message after a period of inactivity, but you also
say this message comes up after clicking login. What is telling you that
this is happening after a period of inactivity?
I was hoping to see what you have for default/user/load (which you
referenced above) - load is not a built-in function in default/user that
I'm aware of.
Here is the normal default/user signature:
def user():
"""
exposes:
http://..../[app]/default/user/login
http://..../[app]/default/user/logout
http://..../[app]/default/user/register
http://..../[app]/default/user/profile
http://..../[app]/default/user/retrieve_password
http://..../[app]/default/user/change_password
use @auth.requires_login()
@auth.requires_membership('group name')
@auth.requires_permission('read','table name',record_id)
to decorate functions that need access control
"""
So I was thinking you had put something custom in there.
Are you able to force it to happen by setting your auth.settings.expiration
to a low number of seconds?
-Jim
On Wednesday, May 6, 2020 at 12:11:55 AM UTC-5, Maurice Waka wrote:
>
> Actually, I want to customize the code to get better feedback, and after
> digging in I got this discussion
> <https://groups.google.com/forum/#!searchin/web2py/not$20authorized$20message%7Csort:date/web2py/k-FnX_X6CcI/fqgUpRbwAwAJ>
>
> I just don't know where to exactly place this code, or get something
> better:
>
> auth.messages.ajax_failed_authentication = DIV(H4(T('Your session has
> expired')),
> T('Please '),
> A(T('login'),
> _href=auth.settings.login_url +
> ('?_next=' +
> urllib.quote(request.env.http_web2py_component_location))
> if request.env.http_web2py_component_location
> else ''),
> T(' again to view this content.'),
> _class='not-authorized alert alert-block')
>
>
>
> On Tue, May 5, 2020 at 11:09 PM Jim S <[email protected] <javascript:>>
> wrote:
>
>> Can you show some code?
>>
>> -Jim
>>
>> On Tuesday, May 5, 2020 at 1:38:29 PM UTC-5, Maurice Waka wrote:
>>>
>>> I notice this message after a period of inactivity. See attached.
>>> The problem is that on clicking on the login link on the app on
>>> pythonanywhere, I get an error: invalid view (default/user/load).
>>> How can I resolve this?
>>> Regards
>>>
>> --
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>> - http://web2py.com
>> - http://web2py.com/book (Documentation)
>> - http://github.com/web2py/web2py (Source code)
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