After clicking the login, that's when the error comes in.
No I haven't set the timer. I left the same time length in default.
Kind regards

On Wed, May 6, 2020 at 3:58 PM Jim S <[email protected]> wrote:

> You said you notice this message after a period of inactivity, but you
> also say this message comes up after clicking login.  What is telling you
> that this is happening after a period of inactivity?
>
> I was hoping to see what you have for default/user/load (which you
> referenced above) - load is not a built-in function in default/user that
> I'm aware of.
>
> Here is the normal default/user signature:
>
>
> def user():
>     """
>     exposes:
>     http://..../[app]/default/user/login
>     http://..../[app]/default/user/logout
>     http://..../[app]/default/user/register
>     http://..../[app]/default/user/profile
>     http://..../[app]/default/user/retrieve_password
>     http://..../[app]/default/user/change_password
>     use @auth.requires_login()
>         @auth.requires_membership('group name')
>         @auth.requires_permission('read','table name',record_id)
>     to decorate functions that need access control
>     """
>
> So I was thinking you had put something custom in there.
>
> Are you able to force it to happen by setting your
> auth.settings.expiration to a low number of seconds?
>
> -Jim
>
>
> On Wednesday, May 6, 2020 at 12:11:55 AM UTC-5, Maurice Waka wrote:
>>
>> Actually, I want to customize the code to get better feedback, and after
>> digging in I got this discussion
>> <https://groups.google.com/forum/#!searchin/web2py/not$20authorized$20message%7Csort:date/web2py/k-FnX_X6CcI/fqgUpRbwAwAJ>
>>
>> I just don't know where to exactly place this code, or get something
>> better:
>>
>> auth.messages.ajax_failed_authentication = DIV(H4(T('Your session has 
>> expired')),
>>                             T('Please '),
>>                             A(T('login'),
>>                               _href=auth.settings.login_url +
>>                                     ('?_next=' + 
>> urllib.quote(request.env.http_web2py_component_location))
>>                               if request.env.http_web2py_component_location 
>> else ''),
>>                             T(' again to view this content.'),
>>                             _class='not-authorized alert alert-block')
>>
>>
>>
>> On Tue, May 5, 2020 at 11:09 PM Jim S <[email protected]> wrote:
>>
>>> Can you show some code?
>>>
>>> -Jim
>>>
>>> On Tuesday, May 5, 2020 at 1:38:29 PM UTC-5, Maurice Waka wrote:
>>>>
>>>> I notice this message after a period of inactivity. See attached.
>>>> The problem is that on clicking on the login link on the app on
>>>> pythonanywhere, I get an error: invalid view (default/user/load).
>>>> How can I resolve this?
>>>> Regards
>>>>
>>> --
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-- 
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