So the answer is :
- "if the object is null, as, in the second test, your use the method 'equals' 
on this object (null) > NullPointerException"

On the first test, as you first test if the object is null, you can't have a 
NullPointerException

Hope this help,

Jérémy

Le 31 juil. 2010 à 14:09, Theodore Petrosky a écrit :

> Yes... I was asking 'Why?' is there a NullPointerException with number 2...
> 
> Ted
> 
> 
> --- On Sat, 7/31/10, Jérémy DE ROYER <[email protected]> wrote:
> 
>> From: Jérémy DE ROYER <[email protected]>
>> Subject: Re: checking for null Noob question
>> To: "Theodore Petrosky" <[email protected]>
>> Cc: [email protected]
>> Date: Saturday, July 31, 2010, 8:07 AM
>> I won't do the second one because you
>> could see a NullPointerException. Is it your question ?
>> 
>> Jérémy
>> 
>> Le 31 juil. 2010 à 14:05, Theodore Petrosky a écrit :
>> 
>>> 
>>> Why does this work:
>>> 
>>> public String dueDateTypeLetter() {
>>>         
>>> if (this.dueDateType() == null ||
>> this.dueDateType().equals("N")) {
>>> return "";
>>> }
>>> return this.dueDateType();
>>> }
>>> 
>>> and this doesn't....
>>> 
>>> public String dueDateTypeLetter() {
>>>         
>>> if (this.dueDateType().equals("N") ||
>> this.dueDateType() == null) {
>>> return "";
>>> }
>>> return this.dueDateType();
>>> }
>>> 
>>> obviously the difference is the order of checking in
>> the 'if' statement...
>>> 
>>> I don't really care that I must check in a specific
>> order... It just took me time to understand that the order
>> was important.
>>> 
>>> Ted
>>> 
>>> 
>>> 
>>> 
>>> 
>>> 
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>> 
>> 
> 
> 
> 



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