Perhaps you need to supply the full pathname. What error message do you
get when you use the approach that I mentioned?
Gary
-----Original Message-----
From: Bruno Verachten [mailto:[EMAIL PROTECTED]]
Sent: Thursday, August 30, 2001 11:27 PM
To: [EMAIL PROTECTED]
Subject: Re: Protocol doesn't support output
Hi Gary,
Gary L Peskin wrote:
>>StreamResult(new File("fromFileToFile.out").toURL().toString()));
>> } catch (java.net.MalformedURLException e) {
>> }
>> }
>>
>>What did I miss?
>>
>
>Have a look at the string created by
> new File("fromFileToFile.out").toURL().toString()
>
>It probably looks funny. In any event, the easiest way to do this is
>to just supply the File as the argument to StreamResult:
>
> ... new StreamResult(new File("fromFileToFile.out"))
>
I had written the line you gave, but it didn't work, so I chose toUrl(),
but it didn't
work either...
Thanks anyway.
B.Verachten.
